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how do i read a unknown size array?i had read i few example from this forum but still dont understandCode:#include<stdio.h>
main(void)
{
int days = 0,count;
float x[unknown size], average, sum;
printf("how many days?");
scanf("%d", &days);
for ( count = 0; count < days; count++) {
sum = 0;
printf("\n Day %d \n how many amount?", count + 1);
scanf("%f", &x[count]);
sum += x[count];
}
average = sum/days;
printf("\n the average sales is %f", average);
return 0;
}
There is no such thing in C. You either have to "oversize" your array (e.g. make it 1000 elements when you never expect more than a couple of hundred), or dynamically allocate the memory once you know the size needed.
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Mats
but then this will come out in exam said by my teacher..Quote:
Originally Posted by matsp
*formula = average = day 1 sales+......+ day n sales / n
To calculate the average, you do not need to store the values in an array - just read in a value at a time and add it to the total - don't need it after you've added it.
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Mats
so where i modified the code?i dont really understand by sentence.. can u point where should i modified?Quote:
Originally Posted by matsp
You needn't make "x" an array - a single float x will be sufficient. And of course, you do not need to index with count.
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Mats
oh but if like that then my code don't have array.. using array is one of the requirement of the question..Quote:
Originally Posted by matsp
Q:* the accountant is able to type in the entire daily sales ammount into the program
* use forumula average = day 1+....+ day n sales/n
*use loop,fuction pointer and array for your programme
Right. So what have you learnt about malloc(), realloc() and free()?Quote:
Originally Posted by archriku
C99 disagrees with you. Declare the array after you read the size.Quote:
Originally Posted by matsp
Quzah.
However, this is not likely to be C99 since default int was used.Quote:
Originally Posted by quzah
I fail completely to see what function pointers have to do with this...
Or is it supposed to say "function, pointers"?
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Mats
Did you stumble into the wrong thread? You're the only one to say the word "funtion" prior to my usage.
Quzah.
I'm not a fan of them anyway. I was just saying it is an option in Standard C now.Quote:
Originally Posted by laserlight
Quzah.
That means we can do something like this according to C99.Quote:
Originally Posted by quzah
But again i doubt whether C99 allows any declaration at any place not just after the curly brace of main.Code:int main(void)
{
int n;
printf("Enter the size");
scanf("%d",&n);
int arr[n];//is this declaration correct after scanf in C99
}
Actually it does. :(Quote:
Originally Posted by BEN10
Quzah.