Need help with problem set

Ok, so my beginning to C programming class has started and I have understood the concepts thus far. There is this one programming excercise I am having an issue with. The excercise asks you to create a program that results in the following output:

Smile!Smile!Smile
Smile!Smile!
Smile!

The only requirement is that I use a function that prints smile once, and then calling upon that function as many times as required to produce the above output. The following is what I have s o far

#include <stdio.h>
int main (void)
{
smile(), smile(), smile();
smile(), smile();
smile();
return 0;
}
void smile (void)
{
printf("Smile!");
}

This is producing an output of

Smile!Smile!Smile!Smile!Smile!Smile!

I know I need a line break ("\n") some where in there, but where. I have tried putting it everywhere and cannot seem to get the require output.

BTW im using Ubuntu Intrepid Ibex server with GCC . My prog is compiling without error, I know I am missing something.

Your help is greatly appreciated!

You should consider using a loop, and a counter, which decreases and keeps track of how many time to call your function before it writes a newline.


Quzah.

between the calls to smile();

Also,

Code:

---

smile(), smile(), smile();

---

is more conventionally written

Code:

---

smile(); smile(); smile();

---

Code:

---

#include <stdio.h>

void smile(void);  // Function prototype ; required if you put your functions
                            //after main

int main (void)
{
  int count1;
  int count2;
 
  for(count1 = 3; count1 > 0; --count1)
  {
      for(count2 = count1; count2 > 0; --count2)
      { 
      smile();
      }
  printf("\n");
  }
return 0;
}
void smile (void)
{
printf("Smile!");
}

---

What about if you had a for loop in main(). It could call smile() every time through the loop, and you could set it up to count backward: 3,2,1


In main()

Code:

---

for( i = 3; i > 0; i--)
  smile(i);

---

In smile:

Code:

---

void smile(int j)  {

for( ; j > 0; j--)
  printf("smile");

print your newline, here.

}

---

So the effect is the same as a double for loop to do this, in main(), but it shows how you want to break apart problems, into smaller sub-problems, and split them up among different smaller functions.

Do you see how the variable i, is turned into j inside smile() ? That's why there's no assignment in smile's for loop, for j. It's already got the right value.

Please don't do people's homework for them. They learn more figuring it out themselves.

God damn you people irritate me. There's a reason I didn't just do the loop for him.


Quzah.

Code:

---

#include <stdio.h>

void smile(int i);

int main (void)
{
  smile(6);
}


void smile (int i)
{
  if(i == 1 || i == 3)
      printf("\n");
 
  if(i){
      printf("Smile!");
      smile(--i);
  }
}

---

Just for fun... and apparrently to irritate quzah
Edited a little now I'm happy.

Code:

---

#include <stdio.h>

void smile (void)
{
  printf("Smile!");
}

int main (void)
{
  for(int i = 6; i != 0; --i)
  {
      if(i == 1 || i == 3)
        printf("\n");
      smile();
  }
}

---

Much better than the first one I posted...

I appreciate all of the ideas, but I think you are all complicating the problem. We were instructed not to use anything that the class hasnt covered yet which would include loops and counters. There has to be a simpler way of doing this. Thanks for all of your responses, I will take it from here. I dont want to upset anyone with my homework.

Quote:

---

Originally Posted by On51aught

We were instructed not to use anything that the class hasnt covered yet which would include loops and counters. There has to be a simpler way of doing this.

---

In that case you should break up your function calls. First, call smile() three times, then call printf() (or puts()) to print a newline. Then call smile() twice, etc.

Thats exactly what I just finished doing. I guess I was also making this problem harder than it really was. I just used a printf function to print a new line. The following is what I got

Code:

---

#include <stdio.h>
void smile (void);
int main (void)
{
smile();smile();smile();printf("\n");
smile();smile();printf("\n");
smile();printf("\n");
return 0;
}
void smile (void)
{
printf("Smile!");
}

---

Again thanks for the help, I am not looking for people to do my homework for me by any stretch, just some boots in the rear towards the right direction. Thanks again to all that responded. I might play with the loop and counter idea just to see if I can get it to work. :)