geting input in C, problem in getting input

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
    while(1)
    {
    char *client_balance[]={"20000", "18000", "16000", "14000", "12000"};
    int client_num=2;
    char buf[6];
    start:
    system("PAUSE");   
    printf("Please type the new PIN:");
    fgets(buf,7,stdin);
    printf("%s\n", buf);
    client_balance[client_num]=buf;
    printf("%s\n", client_balance[client_num]);
    }
 
  system("PAUSE");   
  return 0;
}

---

My Input:
PIN: 123456789
Output:
123456
123456
then it does not wait for my input, it uses the "789" leftover from before,
How to fix this bug? Make it ask me for input each time and use the 6 digits i enter only?

i want the extra numbers to be discarded,
i.e
if first time i entered 123456789
i want before and after to have the first 6 digits
and next time, to ask for my iput again, so that i can enter new numbers

Cprogramming.com FAQ > Flush the input buffer

Why are you trying to read more digits than your buffer holds?

Code:

---

char buf[6];
    start:
    system("PAUSE");   
    printf("Please type the new PIN:");
    fgets(buf,7,stdin);

---

Quzah.

Quote:

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Originally Posted by quzah

Why are you trying to read more digits than your buffer holds?

Code:

---

char buf[6];
    start:
    system("PAUSE");   
    printf("Please type the new PIN:");
    fgets(buf,7,stdin);

---

Quzah.

---

i just wanna know, what happens if we try to read more inputs than declared using fgets().does it functions similar to gets(), i mean it causes buffer overrun.