expected primary expressio before const

Code:

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    case 2:
        cout << "\n Generating an eight number string...";
        numbers[0] = rand() % 9 + 0;
        numbers[1] = rand() % 9 + 0;
        numbers[2] = rand() % 9 + 0;
        numbers[3] = rand() % 9 + 0;
        numbers[4] = rand() % 9 + 0;
        numbers[5] = rand() % 9 + 0;
        numbers[6] = rand() % 9 + 0;
        numbers[7] = rand() % 9 + 0;
        strcat(rand_numb[0], const char*(numbers[0]));
        strcat(rand_numb[1], const char*(numbers[1]));
        strcat(rand_numb[2], const char*(numbers[2]));
        strcat(rand_numb[3], const char*(numbers[3]));
        strcat(rand_numb[4], const char*(numbers[4]));
        strcat(rand_numb[5], const char*(numbers[5]));
        strcat(rand_numb[6], const char*(numbers[6]));
        strcat(rand_numb[7], const char*(numbers[7]));
        generate_password();

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I want to convert the numbers array (an int value) into a const char* array in order to add the string to rand_numb char array. When I try this it says expected primary expressio before "const". Don't know if it matters but I am using Dev-C++ (with MinGW) for my compiler.

You probably want to do a C-style cast, but since the destination type is consists of two words, you would need to use parentheses. However, I suspect that you are on the wrong track: you probably do not want to use strcat, and probably want to do this instead, where I demonstrate the use of static_cast instead of a C-style cast, and fix your +0 bug to +'0':

Code:

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cout << "\n Generating an eight number string...";
rand_numb[0] = static_cast<char>(rand() % 9 + '0');
rand_numb[1] = static_cast<char>(rand() % 9 + '0');
rand_numb[2] = static_cast<char>(rand() % 9 + '0');
rand_numb[3] = static_cast<char>(rand() % 9 + '0');
rand_numb[4] = static_cast<char>(rand() % 9 + '0');
rand_numb[5] = static_cast<char>(rand() % 9 + '0');
rand_numb[6] = static_cast<char>(rand() % 9 + '0');
rand_numb[7] = static_cast<char>(rand() % 9 + '0');
generate_password();

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Though why are you not passing rand_numb to generate_password()?

Quote:

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Though why are you not passing rand_numb to generate_password()?

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I probably forget, it was late at night.

Thank you very much for your help. :D