it won't print the 0 if i enter 102

Code:

---

#include "presults.h"
#include "display.h"
#include "chrutil.h"


int put_result(int ans)
/*  This function is given an integer and prints it one digit at a time
        either to the calc display or the stdout.
*/
{  int wt;        /*  the weight of the msd  */
       
        /*  if the integer is 0, print it and return  */
        if(ans == 0)
        {

                putchar('0');
                ans = ans;
        }
        /*  if the integer is negative, print the '-' and make it pos.  */
        if(ans < 0)
        {

                putchar('-');
                ans = -ans;
        }
        /*  find the weight of the msd  */
        wt = weight(ans);
        /*  while there are more digits  */
        while(wt >= 1)
        {        /*  get msd, convert to char, and print it  */

                putchar(int_to_dig(sig_dig_value(ans,wt)));

                /*  strip the msd  */
                ans = supress_msd(ans,wt);
                /*  go on to next weight  */
                wt = weight(ans);
        }

}


int sig_dig_value(int n, int wt)
/*  This function is given and integer and the current weight.  It
        returns the integer value of the most significant digit.  */
{  return n/wt; }

int supress_msd(int n, int wt)
/*  This function is given an integer and the current weight.  It
        returns an integer with the most significant digit removed.  */
{  return n % wt;  }

int weight(int n)
/*  This function is given an integer.  It returns the weight  (a power
        of 10) of the most significant digit.  */
{  int wt = 1;

        while((n/wt) != 0)
                wt = wt * BASE;

        wt = wt / BASE;
        return wt;
}

---

all other numbers work well besides 0.
if i put 10001 it prints 11
if i put 102 it prints 12...

Wow, that's a lot of code for something that I'd probably write in 5-7 lines.

Code:

---

        while((n/wt) != 0)
                wt = wt * BASE;

---

This effectively prevents any "zero" values from being printed, I think.

Here's my obfuscated solution [it doesn't deal with negative tho'] (don't use this!):

Code:

---

void printnumber(int n)
{
    char str[13]={}, *s=&str[12];do{*--s='0'+n%10;n/=10;}while(n);
    puts(s);
}

---

--
Mats