Static array of initialized members?

Probably not the best description; I'm building a simple class structure for my tokenizer and I want all initialized members of the class to be put into an array.

Unfortunantly; my compiler is yelling at me when I dump them into an array; could anyone point out how to actually accomplish this? Nothing I do seems to work t-t.

Code:

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class Token {
        public:
        std::string token;
        int opcode;
        bool type;
        static Token Tokens[32];
        static int NTokens;

        Token(std::string a, int b, bool c) {token = a; opcode = b; type = c; Tokens[NTokens++] = this;}
        Token(char a, int b, bool c) {token[0] = a; token[1] = '\0'; opcode = b; type = c; Tokens[NTokens++] = this;}
};

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I'm sure it's something simple; but I just don't see it.

You are declaring a static array of 32 Tokens. That is going to create 32 token objects the same way that static int integers[32] would create 32 integers. Now which constructor is going to get called when those 32 Token objects get created?

Quote:

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Originally Posted by bithub

You are declaring a static array of 32 Tokens. That is going to create 32 token objects the same way that static int integers[32] would create 32 integers. Now which constructor is going to get called when those 32 Token objects get created?

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I always thought C++ compiled types before declarations; but I'm not really well versed in how it's compiled. If that's the case - do you have any recomendations on how to do this? I'd like to avoid dynamic memory allocation in this particular instance.

[Edit]

Ughh I'm an idiot; I forgot the compiler doesn't supply a default blank constructor if you supply your own. Thanks for the help!

Blahhh; hate to bump this but my workaround doesn't work t-t. I can't figure out a single way to initialize a list of members without actually making a linked list; I can't even figure a way to use vectors for this ~ it's trying to initialize any data member before the constructor in announced t-t.

>> token[0] = a; token[1] = '\0';

That's a really bad idea. You don't add characters to an std::string that way. Use string::push_back(char) or string::operator += (const char*). Furthermore, you should *never* terminate, resize, append, or otherwise alter the dimensions of an std::string manually (so no strcpy, strcat, etc). Always use the appropriate member functions for those sorts of operations.

Anyway, here is an example of using a vector for your data structure:

Code:

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class Token {
        public:
        std::string token;
        int opcode;
        bool type;
        static vector<Token> Tokens;

        void init(std::string a, int b, bool c)
        {
                token = a;
                opcode = b;
                type = c;
                Tokens.push_back(*this);
        }
       
        Token(std::string a, int b, bool c)
        {
                init(a, b, c);
        }
       
        Token(char a, int b, bool c)
        {
                char temp[2] = {a, 0};
                init(temp, b, c);
        }       
};

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