Newbie C Programer Needs Help ASAP

Well I am curentley taking a C class at my school and am working on a code right now and I am having quite a bit of Trouble. I know most of you have more experance than I therefore I will post what is needed and what I have thus far...I am having troubles with the for loop is there anyway instead of printing out 4
3
2
etc I could get it to throw out the correct amount of * for the number it is inplace of ?

This is what I have so far

/* Written by:
UT
Assignment Number Four
Feb. 21, 2002
*/

#include <stdio.h>
#include <conio.h>

void main (void)
{
int a,z;
do{
printf("Please enter an odd number greater than five...");
scanf("%d", &a);
z=a%2;
}
while (a<5||z<1);

for(z=a ; z > 0; z=z-1)
{
printf("%d\n",z);
}




getch();
}

This is what the Assigment requires.

Use a combination of different structures you have learned to far (sequences, conditions, jumps and loops) to create an output to form:

**********
*******
*****
***
*

You should ask the user to enter an odd number.
Check and discard even, and negative numbers
Odd numbers less than 5 should also be discarded.
Each row has two stars less than the one above

Okay as you can see I am pretty lost any help is appraicted thanks in advance guys

Try something like.....

Code:

---

#include <stdio.h>
#include <conio.h>

int main()
{
    int x,y;


    printf("\n\tInput Number (Greater than 5, Not Even): ");
    scanf("%i",&x);

    if ((x<5) || (x%2=0))
    {
        printf("\n\tInvalid Entry!");
        return 0;    // Quits the Program //
    }
}

---

that's all i'm giving you...it's pretty muh what you had....structured bit better......all you need to do now...is to add a loop after that whole if statement....firs you want the loop to be executed the same amount of times as x, and the only thing in the loop should be a printf("*"); so the loop will just print an x amount of astrieks..then after that....every other line will have a (x-2) amount of stars........you should be able to figure it out now ...try it.

you probably want something like this:

int num //I'll leave getting this value to you.

for(num; num >= 0; num--)
{

numcopy = num;

for(numcopy; numcopy >= 0; numcopy--)
{
printf("*");
}

printf("\n");
}

that should give you the results you're looking for.

-starX
www.axisoftime.com

I am not familair with num copy can someone tell me what this function does ? Sounds like it could be useful in the future if it does what I think it does :-)

Hi,
the numcopy that star x has shown as an example is not a actual function but is an integer varaible used as example to yourself as a counter...he could have easy have taken the option of using the more preferred counter variable names of count, i or j.

Code:

---

int num; /* for user input */
int i, j; /* counters  */
/* rest of your code ..then */
for(i = num; i >= 0; i--)
{

j= i;

for(j; j>= 0; j--)
{
printf("*");
}

printf("\n");
}

---