setting structure char array with string

Hello,

sorry if this seems like a trivial query but I was having some issue setting a string to a char array in a structure. I have a set up like this:

Code:

---


typedef struct
{
int date; char name[20];
} call[2];

call iec;
call.date = 1022009;
call.name ="TEST";

---

I can get the date set but not the string.


Also the call[2] at the end of the structure definition this means that I can hold 2 structures right? Here I only set up one, called iec.

Code:

---

#include <string.h>

typedef struct
{
  int date;
  char name[20];
} call; /* this is type */

int main(void)
{
  call iec; /* this is object of the type call */
  call something[2]; /* this is array of two objects of type call */
 
  iec.date = 1022009;
  strcpy(iec.name,"TEST"); /* this is a way to copy strings in C */
  return 0;
}

---

Your whole declaration thing is wrong.
It should be

Code:

---

typedef struct
{
 int date;char name[20];
} call;

call iec;
iec.date = 1022009
strcpy(iec,name, "TEST");

---

Quote:

---

Originally Posted by vart

Code:

---

#include <string.h>

typedef struct
{
  int date;
  char name[20];
} call; /* this is type */

int main(void)
{
  call iec; /* this is object of the type call */
  call something[2]; /* this is array of two objects of type call */
 
  call.date = 1022009;
  strcpy(call.name,"TEST"); /* this is a way to copy strings in C */
  return 0;
}

---

---

Shouldn't that be

Code:

---

something[0].date = 1022009;

---

?

Thanks you vart, much appreciated. It worked with a single object, will try with an array of structures now.

Also got it working for arrays. Great.

Thanks again!

Quote:

---

Originally Posted by PING

Shouldn't that be

Code:

---

something[0].date = 1022009;

---

?

---

yeah, have missed that part in the original code... fixed it