mistake of using awk

Hi,
Here is my code,

Code:

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ids=(1 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 90 100 110 120)
for ((i=0;i<${#ids};i++)); do
  awk '{ print ${ids[${i}]}" "$1; }' > ${TMP} < ./results/$1${ids[${i}]}/test_error.dat
done

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I got this error

Quote:

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awk: { print ${ids[${i}]}" "$1; }
awk: ^ syntax error
awk: { print ${ids[${i}]}" "$1; }
awk: ^ syntax error
awk: fatal: invalid subscript expression

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Could you please explain what mistake I made? Thanks in advance!

Shell variables aren't available within awk. What shell are you using?

Quote:

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Originally Posted by lehe

Code:

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  awk '{ print ${ids[${i}]}" "$1; }'

---

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Those single quotes are preventing shell variable expansion. Try using double quotes instead, and escape the inner double quotes and awk variable $:

Code:

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awk "{ print ${ids[${i}]}\" \"\$1; }"

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EDIT: Note that your use of $1 in the results redirect won't work, because $1 is an awk variable which can't be accessed from the shell level.

I am using bash.
The $1 in

Code:

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'{ print ${ids[${i}]}" "$1; }'

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was intended to be read by awk as the first field in the file

Code:

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"./results/$1${ids[${i}]}/test_error.dat"

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, where the $1was intended to be the 1st argument from command line calling this bash script.

Quote:

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Originally Posted by lehe

I am using bash.
The $1 in

Code:

---

'{ print ${ids[${i}]}" "$1; }'

---

was intended to be read by awk as the first field in the file

Code:

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"./results/$1${ids[${i}]}/test_error.dat"

---

, where the $1was intended to be the 1st argument from command line calling this bash script.

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Ah. In that case, I think just changing the quoting should work.

Thanks!
What I actually want to do is to read from a bunch of files test_error.dat each of which cantains single number, and write them into a single file "${TMP}" as
1 num1
5 num5
10 num10
15 num15
...
Each row has a space between the two numbers. That's why I put a double-quoted space in print before $1.

If I change single quote to double quote as

Code:

---

ids=(1 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 90 100 110 120)
for ((i=0;i<${#ids};i++)); do
  awk "{ print ${ids[${i}]}" "$1; }" > ${TMP} < ./results/$1${ids[${i}]}/test_error.dat
done

---

I will get

Quote:

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awk: cmd. line:1: { print 1
awk: cmd. line:1: ^ unexpected newline or end of string

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Quote:

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Originally Posted by lehe

Thanks!
What I actually want to do is to read from a bunch of files test_error.dat each of which cantains single number, and write them into a single file "${TMP}" as
1 num1
5 num5
10 num10
15 num15
...

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If that's the case try this script:

Code:

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awk '{print $1, "num"$1}' test_error.dat > outputfile

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