Quick Sizeof Question

At the top of my program I created a definition:

Code:

---

#define CRLF "\r\n"

---

Which seems to work just fine except for the fact that the sizeof(CRLF) returns 3 when I would expect the result to be a 2. Is this just a mistake on my part?

Thanks,

PetrolMan

Code:

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\r = 1
\n = 1
\0 = 1
  ----
    3

---

\0 is a Null Character Right?

Is there a way to prevent the \0 from being put in or is that even desirable in the first place?

PetrolMan

Every "string literal" ends with a null character. Whether you want that or not depends on how you use CRLF.

There's a multicharacter constant:

Code:

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#define CRLF '\r\n'

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However that's implementation-defined behaviour, and wont be a direct replacement because then suddently it's not even an array.
I don't think it makes sense to use sizeof on it. If you'd rather avoid using strlen on it, then just declare another constant with the value 2.