Is This Supposed To Happen? [Dynamic Memory]

I'm calling the following function:

Code:

---

unsigned int Test(void)
{
    char *var;
   
    var = (char*) malloc(255);
    memset((void*)var,0,254);
   
    strcpy(var,"A string.");
   
    free(var);
   
    MessageBox(NULL,var,"Data in var",MB_OK);
   
    return 0;
}

---

And, for some reason, even though it's been free()'d, I'm still getting this: (see attachment).

Is this supposed to happen? o_O

You can get anything and everything by using freed memory. All this means is that either (a) the memory has yet to be reassigned and/or (b) the new owner hasn't written new stuff in it yet. The memory is not trashed when freed.

Oh, that makes sense. Thanks p_o

A free pointer still points to the same address. You could use var=NULL.

ps. your memset does not need to be one byte smaller than your malloc, since they both refer to the number of (not "the count beginning with zero").