Converting an int to an address in an array
Hello. This is my first post and I welcome any and all advice on this particular program I am writing. I am trying to take any int value and convert it to a constant address off an array. For instance, if I enter the value 8, the output should be 0x08 as a string. I suspect there maybe a simpler way of doing this, but I am at a loss. I get the following errors when I compile:
main.c:54: warning: passing arg 1 of `ConvertStringToTable' makes integer from pointer without a cast
main.c:57: error: syntax error before '(' token
main.c:57:17: warning: multi-character character constant
main.c: In function `ConvertStringToTable':
main.c:61: error: syntax error at end of input
Eventually I want to take micro controller output as an int value and produce a matching address which I will use for an on screen display, but I'd like to get this simpler version working first.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
//
// defining constants
const unsigned char charcodetable[] =
{
0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0A,
};
const unsigned char ascii_table[] =
{
'1','2','3','4','5','6','7','8','9','0',
};
unsigned char ConvertStringToTable (unsigned char data)
{
unsigned char outchar=0x99;
unsigned int i;
for (i=0; i< sizeof(ascii_table); i++)
{
if (data == ascii_table[i])
{
outchar = charcodetable[i];
break;
}
}
if (outchar!=0x99)
{
return outchar;
}
else
{
return data;
}
int main()
{
int num = 1;
unsigned char buf[15];
unsigned char dummy;
itoa (num, buf, 10);
printf("%s\n", buf);
do
{
dummy = ConvertStringToTable (buf);
printf ("%s\n",dummy);
} (dummy != '0x99');
System ("Pause");
return 0;
}
