warning: passing argument 1 makes pointer from integer without a cast

I get the above warning with the following code. I have used this same process in the past without any warning. I have not been able to eliminate the warning.

Code:

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//FUNCTION

int FUPW_f(int *index, int i)  //Pulse Width Function
        {       
                int j;
                int FPW;
                if (i > 3) j = 1;
                else j = 0;               
                FPW = *(index + j);
                return FPW;
        }
//main

int FULPW[8];
int FUPW_REG[2];
int PWOFF;


for (i = 0; i < 8; i++)               
        {
                FULPW[i] = (FUPW_f(*FUPW_REG, i) + PWOFF);       
        }
        }

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FUPW_REG is an array of integers hence *FUPW_REG is the first integer in the array. FUPW_f's first parameter is a pointer to an integer, so what you should probably do is pass FUPW_REG instead of *FUPW_REG since the array would be converted to a pointer to its first element.

By the way, a common convention is to reserve fully capitalised names for macro names.

laserlight,

When I do that, I get:

warning: passing argument 1 of 'FUPW_f' discards qualifiers from pointer target type

Perhaps you're passing a const pointer to a function that expects a non-const pointer?

Quote:

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Originally Posted by dwks

Perhaps you're passing a const pointer to a function that expects a non-const pointer?

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OK, that's it. I was passing a volatile integer to a non-volatile pointer. It's working now. Thanks.