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If Problem
Code:
if(input == "LOL")
{
random = (rand() % ( 1 - 6 )) + 1;
if( random == 1)
{
cout <<"You Stumble along the dirt road and find a penny\n";
money = money + 1;
if(counter >= 1)
{
counter = counter - 1;
}
}
if( random == 2)
{
cout <<"You reach into yer moms pocket and pull out a penny\n";
money = money + 1;
if(counter >= 1)
{
counter = counter - 1;
}
}
if(random == 3)
{
cout <<"As you search your couch you find a penny\n";
money = money + 1;
if(counter >= 1)
{
counter = counter - 1;
}
}
if(random == 4 && counter == 0)
{
cout <<"As you wander helplessly down the street you get knocked in the head.\n"
<<"You wake up later to find yourself in a alley and yer pockets empty\n";
money = 0;
counter = 5;
}
if(random == 5)
{
cout <<"You ask the mayor for bebe mooneys he gives u a penny\n";
money = money + 1;
if(counter >= 1)
{
counter = counter - 1;
}
}
if(random == 6)
{
cout <<"You Beg for mooneys and recieve a penny for a hard days work\n";
money = money + 1;
if(counter >= 1)
{
counter = counter - 1;
}
}
}
For some strange reason when typing this it will some times not say any thing but it never says number 6 and im not sure why btw this is a snippet of the code not all
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The possible values of the % are 0, 1, 2, 3, and 4. Adding one gives 1, 2, 3, 4, and 5. So not getting 6 is exactly what you should expect.
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