freaky output!

Can any one tell me why the out put is "1 40 0" and not "1 40 1"

Code:

---

main()
{
    int x;
    printf("%d%d%d",x<=50,x=40,x>=10);
    getch();
}

---

cheers!

It's undefined.

The standard emposes no order of which arguments are evaulated, that's up to the compiler (and optimization it might do*).

* Which may change the result when optimizations are on or off for example.

You have not initialized x so it's value is undefined. Also it is undefined what the order of argument evaluation is, so you do not know whether or not x=40 happens before x>=10, and obviously in this case it doesn't.

Why would you be doing something like this?

The obvious "fix" is;

Code:

---

int main(void)
{
  int x = 2;
  int a, b;

  a = (x <= 50);
  x = 40;
  b = (x >= 10);

  printf("&#37;d %d %d\n", a, x, b);
  return 0;
}

---

Quote:

---

Can any one tell me why the out put is "1 40 0" and not "1 40 1"

---

it completely depends on the compiler used.also as x is undefined , any garbage value is taken up and according to this value & the order of argument evaluation the compiler produces the output.