Function name as template parameter?

Is it possible to pass a function name as a template parameter? Here's an abstraction of what I'm trying to do. Another possible complication is that I'm trying to assign a default function that is part of a namespace:

Code:

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namespace foo{
    void fighter();
}

template <function = foo::fighter>
class a_class;

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What do you mean, here? You don't ever specify anything about a typename when you declare a template.

Assuming that you want to define the class template instead of just declaring it, you might write this:

Code:

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typedef void (*Function)();

template<Function function = foo::fighter>
class a_class;
{
    // ...
};

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Quote:

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Originally Posted by laserlight

Assuming that you want to define the class template instead of just declaring it, you might write this:

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Yes, I do. That was just an abstraction.

And the compiler accepted that, so I guess that was it. Thanks.