Need help with arrays..

Lets say I have the array[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 } and I want to pick 4 of those arrays, somewhere in the middle... like for an example, I want to only use 4 of those elements starting at 3... in that way, it prints out 3, 4, 5, 6... How do i do this using arrays?

Just search for the element whose value is 3, then take it and the next three elements.

How do i do that, like I'm just learning about arrays...

Do you know how to access a particular element of an array?

Do you know how to repeat a statement (or group of statements) repeatedly until some condition is met?

also, the lets say the array will change here and there, so I won't be able to search for 3 if there isn't a 3 in the array. I want to pick the "third " element in the array and that is what I want to know, sorry that i was confusing.

How would you search for an element with the value of 3? Provide some example code.

Quote:

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I want to pick the "third " element in the array and that is what I want to know, sorry that i was confusing.

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The third element in the array is array[2].

Code:

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/*
 * I want to print out how many elements in the array starting with the index given
 * function for pick is pick(int many, int starter, arr[])
 * My output with int array[] = {1, 5, 6, 8, 1, 10, 11, 13};
 * pick(4, 3, array);
 * 8 1 10 11
 *

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Okay, so now we'll add "do you know how to repeat a statement (or group of statements) a fixed number of times?" to the list.

I only know how to do things like "while this is true, do this, until its proven false" or "for(i=0;i<0;i++).. I dunno if this helps.

I've been working on it, I guess the for loop is used here and i thought i had it, but... nothing happens.

Code:

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void pick(int many, int starter, int arr[]) {
        int i, s, h;
        many= h;
        starter= s;

        for(i=s;s<h;i++)
        {
                printf("&#37;d ", arr[i]);
                fflush(stdout);
        }
}

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You should give your variables descriptive names. Okay, we can make an exception for i since it is a conventional name for a loop/array index, but s and h are meaningless. Worse still, you assign h to many, but h was not initialised, and you clearly want to use the value of many.

Your loop itself either does not run or does not terminate (in theory) since if s < h, then s is always less than h since neither s nor h change in the loop body.

So for loops do things for a fixed number of times, yes. So:

1. How many times do you want your for loop to run?
2. How do you write a for loop that runs that many times?
3. If this is the i'th iteration of the loop (where i = 0, 1, 2, ... ?) what array index do you want to access?
4. How do you access and print that array element?

Quote:

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Originally Posted by tabstop

So for loops do things for a fixed number of times, yes. So:

1. How many times do you want your for loop to run?
2. How do you write a for loop that runs that many times?
3. If this is the i'th iteration of the loop (where i = 0, 1, 2, ... ?) what array index do you want to access?
4. How do you access and print that array element?

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Well I want to loop it on the number of "many" that is put into the function pick.
I want to access the "starter" part of the array, so if number 3 is put into the function, then i want it to start at that element.
Well, the only thing I can think of is... "%d" or "%s".

Its all good you guys... I can't solve it, been thinking about it for like 1.5 hours now.. but I won't give up... I know there is a way to do it and i know its possible. I just need to find out how :D but thanks though.

Do you just mean this?

Code:

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void pick( int many, int starter, int arr[])
{
        int i;

        for (i = starter; i < starter + many; i++)
                printf( "%d ", arr[i]);
        printf( "\n");
}

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BTW, programmers often work in groups, so you should work on your communication skills!

yeah, thats what I got. Thanks though. ^^