Hello
Why will the following code output integer c as 0 (null)?
What would be the proper way of calculating 2^1000 in c++?Code:unsigned int c = pow( (double)2 , (double)1000);
std::cout << c << "\n";
Thanks a lot!
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Hello
Why will the following code output integer c as 0 (null)?
What would be the proper way of calculating 2^1000 in c++?Code:unsigned int c = pow( (double)2 , (double)1000);
std::cout << c << "\n";
Thanks a lot!
An unsigned int is unable to store values larger than 2^32.
I believe a double would be able to store it. Otherwise you would need a to use a bignum library.
Even if a double can store it, it won't be with infinite precision. You will only get a few significant figures.
If you want the answer with infinite precision, you will have to use a bignum library.
Actually: (2^32)-1 is the largest you can fit in a 32-bit integer.Quote:
Originally Posted by Waterbottle
A double should be able to store 1.07E301, which is roughly the value of 2^1000.
--
Mats
Oh and just poking, but in C++, it is really in our best to use the C++ variants of the C functions, std::pow.
There should be one, no?