how can i use sleep in my code..

what i need to know is how can i make the numberzz go like
1 then rest for a sec
2 then rest for a sec
3 do the same as above
4 same....

now how can i do this in my code....

#include <stdio.h>

int main()

{
int count;

for(count=10;count>0;count=count-1)
printf("%i\n",count);

}

First:
> count=count-1

Usually people use count-- It does the same thing.

Also, how to sleep depends on the compiler.

If it's a windows compiler, then one option is:

#include <windows.h>
.
.
Sleep(1000); //Sleep 1 second

If you choose not to use <windows.h> and use Sleep(), I believe you can use <dos.h> and use Delay(). It works the same as sleep and is measure in miliseconds, so Sleep(3000) will sleep 3 seconds.

Example of Sleep for a Simple Progress Looking Bar:

Code:

---


#include <stdio.h>
#include <windows.h>

void main()
{
        int x;

        printf("\n\t[.....]\b\b\b\b\b\b");
        for (x=5; x>0; x--)
        {
                Sleep(130);
                printf("-\b");
                Sleep(130);
                printf("+\b");
                Sleep(130);
                printf("*");
        }

        printf ("\n\n\t");

}

---

enjoy.

Quote:

---

Originally posted by swoopy
If it's a windows compiler, then one option is:

#include <windows.h>
.
.
Sleep(1000); //Sleep 1 second

---

...and on POSIX systems (Linux, UNIX, etc), the argument for sleep() is in seconds:

Code:

---

sleep(1);  /* sleep for one second */

---