Completely Clueless!!

Hello, I have this program to do and I'm completely clueless on how to get started. Any suggestions will be greatly appreciated.

Write a program to convert Celsius to Fahrenheit or Fahrenheit to Celsius depending on the user’s choice.
a. Use main( ) as the driver function. main( ) should allow the user to run the program as many times as desired.
b. Write the function getConvertChoice( ) to prompt the user for the desired conversion:
1. Celsius to Fahrenheit
2. Fahrenheit to Celsius.
Return this value back to main( ).
c. Write the function getTemperature( ) to prompt the user for the temperature in degrees to be converted.
d. Depending on the user’s conversion choice: 1) call the function convertToFahren( ), if the user chose to convert from Celsius to Fahrenheit, or 2) call the function convertToCelsius( ) if the user chose to convert from Fahrenheit to Celsius. The formulas are:
Fahrenheit = (9.0/5.0) * Celsius + 32.0
Celsius = (5.0/9.0) * (Fahrenheit – 32.0)
e. Write the function displayConversion( ) to display the original temperature entered and the converted temperature with appropriate messages. Display the values to a tenth of a decimal.

hello, first of all you need to know the formula that can converts these two to one another!
a formula that converts Celsius to Fahrenheit is "F=(9.5/5.5)*c+32 where C is temp in Celsius !
about main. it is announcing that you should make a console application. where your duty is to place two other functions inside that and also respectively the other needed function , the program is rather easy to implement , look at the sample code i wrote . dont copy it ~ it may have errors , cuz i didnt pay a carful attention to it ! and just wanted to show you the steps !
so Good luck

Code:

#include <@#> void convertToCelsius(double); void convertToFahren(double); int getConvertChoice( int); double getTemperature(int ); int main() { int x; getConvertChoice(x); getTemperature(x); return 0; } double getTemperature(int choice) { if (choice ==1) convertToFahren( ); else convertToCelsius( ); } int getConvertChoice(int x) { } void convertToFahren(double z ) { ~ ~ ~ cout<<z<<endl; } convertToCelsius(w ) { ~ ~ ~ cout<<w<<endl; }

Not sure I understand.....

what is it that you dont understand? and where?

Seems like he wants his homework done for him, that is a basic beginning homework assignment.

If you are going to post code, at least indent it properly.
And do not just hand out code or answers to the newbies. It will teach them nothing.

Quote:

Originally Posted by Masterx

hello, first of all you need to know the formula that can converts these two to one another!
a formula that converts Celsius to Fahrenheit is "F=(9.5/5.5)*c+32 where C is temp in Celsius !
about main. it is announcing that you should make a console application. where your duty is to place two other functions inside that and also respectively the other needed function , the program is rather easy to implement , look at the sample code i wrote . dont copy it ~ it may have errors , cuz i didnt pay a carful attention to it ! and just wanted to show you the steps !
so Good luck

Code:

#include <@#> void convertToCelsius(double); void convertToFahren(double); int getConvertChoice( int); double getTemperature(int ); int main() { int x; getConvertChoice(x); getTemperature(x); return 0; } double getTemperature(int choice) { if (choice ==1) convertToFahren( ); else convertToCelsius( ); } int getConvertChoice(int x) { } void convertToFahren(double z ) { ~ ~ ~ cout<<z<<endl; } convertToCelsius(w ) { ~ ~ ~ cout<<w<<endl; }

Yeah... That code formatting is just ridiculous and it's even worse to give it to noobs.

Quote:

Originally Posted by Elysia

If you are going to post code, at least indent it properly.
And do not just hand out code or answers to the newbies. It will teach them nothing.

just tried to show him the outline !
and help !
if any thing was/is wrong i'll appriciate your comment .
(is it now indented properly?!)

Quote:

Originally Posted by Masterx

just tried to show him the outline !
and help !

Yes, and it gives away a huge amount of information that you are merely giving away that they themselves should be able to do.
The best thing would be for the OP to do what code he/she can, consult the books and ask questions if there is something in there that he/she does not understand, which would be where we come in.

Quote:

(is it now indented properly?!)

Is it indented? Yes.
Properly? No.

This is an example of how properly indented code should look like:

Code:

#include <@#> void convertToCelsius(double); void convertToFahren(double); int getConvertChoice( int); double getTemperature(int ); int main() { int x; getConvertChoice(x); getTemperature(x); return 0; } double getTemperature(int choice) { if (choice ==1) convertToFahren( ); else convertToCelsius( ); } int getConvertChoice(int x) { } void convertToFahren(double z ) { ~ ~ ~ cout<<z<<endl; } convertToCelsius(w ) { ~ ~ ~ cout<<w<<endl; }

And also a word of advice: do not strip the names of the parameters in the function prototypes. Just... do not.
And convertToCelcius also lacks return type and parameter type, so it is even more bad.

And a sidenote, your function names "convertToCelsius", "getTemperature" and so on, kind of imply that the functions return the value passed to it (get/set), as celsius/fahrenheit, however they only seem to convert and then print them to stdout, never really returning anything to main(). Perhaps a more fitting name would be printAsCelsius or outputCelsius etc, might aswell use proper names, makes the coder easier to follow and easier for others to use.

And finally, look at the main() function you provided, x is never initialized, the value is never changed (regardless of what getConvertChoice is supposed to do), so the value that is passed to getTemperature is some random gibberish, which will obviously yield very incorrect output.

This is so basic a program that if jap2010 had done a google search he/she would find the code.

If this homework is giving them problems then they are either extremely lazy and never opened their book, or retarded. I would have loved to be able to use the internet when I was in beginning programming classes. Unfortunately Al Gore hadn't invented it yet. :D

Quote:

Originally Posted by Elysia

Yes, and it gives away a huge amount of information that you are merely giving away that they themselves should be able to do.
The best thing would be for the OP to do what code he/she can, consult the books and ask questions if there is something in there that he/she does not understand, which would be where we come in.

Is it indented? Yes.
Properly? No.

This is an example of how properly indented code should look like:

Code:

#include <@#> void convertToCelsius(double); void convertToFahren(double); int getConvertChoice( int); double getTemperature(int ); int main() { int x; getConvertChoice(x); getTemperature(x); return 0; } double getTemperature(int choice) { if (choice ==1) convertToFahren( ); else convertToCelsius( ); } int getConvertChoice(int x) { } void convertToFahren(double z ) { ~ ~ ~ cout<<z<<endl; } convertToCelsius(w ) { ~ ~ ~ cout<<w<<endl; }

And also a word of advice: do not strip the names of the parameters in the function prototypes. Just... do not.
And convertToCelcius also lacks return type and parameter type, so it is even more bad.

many tanx Dear Elysia. i will definitely remember that.(indention )
and about the functions, i really didnt pay a careful attention , as i mentioned explicitly before , i just wanted to show him/her how it could be in a terms of function!.thats why i missed couple of stuff !
(and because i was using notepad to write those codes, and meanwhile forgot about the Tab to indent properly , thats what it looks like now!

i wont correct the problems(or should i correct it? i dont know?) , because if i do this would spoil the fact that hes is learning.!and by doing such a thing he/she wont learn it though!

Quote:

Originally Posted by Neo1

And a sidenote, your function names "convertToCelsius", "getTemperature" and so on, kind of imply that the functions return the value passed to it (get/set), as celsius/fahrenheit, however they only seem to convert and then print them to stdout, never really returning anything to main(). Perhaps a more fitting name would be printAsCelsius or outputCelsius etc, might aswell use proper names, makes the coder easier to follow and easier for others to use.

And finally, look at the main() function you provided, x is never initialized, the value is never changed (regardless of what getConvertChoice is supposed to do), so the value that is passed to getTemperature is some random gibberish, which will obviously yield very incorrect output.

many tanx darling, :) i said the reasons above! and by the way YOu ve just made a point here that i didnt paid attention before , tanx for the tip !

Quote:

Originally Posted by DaveH

This is so basic a program that if jap2010 had done a google search he/she would find the code.

If this homework is giving them problems then they are either extremely lazy and never opened their book, or retarded. I would have loved to be able to use the internet when I was in beginning programming classes. Unfortunately Al Gore hadn't invented it yet. :D

people have different reasons for their question , we shouldnt make fun of them cuz they dont understand sth because of sth!! its just ridicules ! sorry but i think the term retarded is not proper ! to be called to any one specially here!
( but i go along with you in terms of searching before asking)!

I really appreciate you guys and your great tips . tanx , hope these things help newbies like me flourish faster ! :)

Okay, lets change it to mentally handicapped. ;)

Seriously, if they have read and studied their book or did a quick internet search, and they still have no clue at all on how to start, then they have something wrong with their brain.

many thanks