Sockets: IPv4 vs IPv6

Hello everyone in C Boards! I'm here to look again for answer or hints to help me accomplish what I need to do...

I'm writing a server with sockets (actually, a repository of files), and I have a code (see down). The code shouldn't care about IPv4 and IPv6. When a IPv6 interface connects to the server, everything is printed fine and the IP appears ok. Anyway, when a IPv4 connect to the repository the IP appears in a IPv6 style...

I know that they are the same address expressed in different ways, but I need it to print the IP as a IPv4 without the ::fffff: prefix...

Example:
Aceptada conexión de ::ffff:127.0.0.1
should print
Aceptada conexión de 127.0.0.1

The code:

Code:

---

        printf("Esperando conexiones por el puerto %s...\n",puerto);
       
        // Manejo de conexiones, etc
        while(1){
                sizeClient = sizeof(struct sockaddr_storage);
                socketClient = accept(socketId, (struct sockaddr *)&infoClient, &sizeClient);
                if(socketClient==-1){
                        perror("aceppt");
                        continue;
                }
                char s[INET6_ADDRSTRLEN];
                inet_ntop(infoClient.ss_family,
                          (void*)direccionIn((struct sockaddr_in *)&infoClient),
                          s, sizeof(s));
                printf("Aceptada conexión de %s\n", s);
               
                // Todo el código aqui
                // All the code here
               
               
                printf("Cerrando conexión de %s\n", s);
                close(socketClient);
        }

---

And the direccionIn:

Code:

---

void *direccionIn(struct sockaddr *sa) {
        // Si es IPv4
        if (sa->sa_family == AF_INET) {
                return &(((struct sockaddr_in*)sa)->sin_addr);
        }
        // Si es IPv6
        return &(((struct sockaddr_in6*)sa)->sin6_addr);
}

---

I've added another question... Anyone can give me some light on this? :S :)