Easy Pointer question

char string[30];
char *ptr_string;


how do i copy ptr_string and put it into string?

like this?

Code:

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string = strdup(ptr_string);

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what about the other way?

Code:

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ptr_string = strdup(string); ? or  is it
ptr_string= (char *)malloc (strlen(string) * sizeof(char));

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The way strdup() is described, you'd do something like:

Code:

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ptr_string = strdup(string)

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but by the way you worded the question you want it assigned the other way around? There is no storage allocated for ptr_string yet. Only the array string[] has storage so far. Your guesses seem to be more like what I have. strdup does an implicit malloc for you.