Problem with argv[]

My program is supposed to read numbers from a .txt or .bin file and then print them into the opposite file type. When running the program, command line is ./programname -x file1 file2 (where x is -t for reading text or -b for reading binary). The problem is when it calls for the argv[1] value of either -t or -b the program exits.
Any suggestions so it'll actually get to the read and writing stages of the problem?
Thanks.

Code:

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#include <stdio.h>
#include <stdlib.h>

void getinfo(double a[], int n, FILE *file1, FILE *file2);

int main(int argc, char *argv[])
{
  FILE *fp1, *fp2;
  double a[100];
  int i;
  if (argc != 4) {
    printf("No file names given, program exit\n"); exit(EXIT_FAILURE);
  }

  if (argv[1] == "-t") {
    fp1 = fopen(argv[2], "r");
    if (fp1 == NULL) { printf("Error!\n"); exit(EXIT_FAILURE); }
    fp2 = fopen(argv[3], "wb");
    if (fp2 == NULL) { printf("Error!\n"); exit(EXIT_FAILURE); }
    getinfo(a, 100, fp1, fp2);
  }
  else if (argv[1] == "-b") {
    fp1 = fopen(argv[2], "rb");
    if (fp1 == NULL) { printf("Error!\n"); exit(EXIT_FAILURE); }
    fp2 = fopen(argv[3], "w");
    if (fp2 == NULL) { printf("Error!\n"); exit(EXIT_FAILURE); }
    getinfo(a, 100, fp1, fp2);
  }
  else{
    printf("Fail.\n");
    exit(EXIT_FAILURE);
  }
  fclose(fp1);
  fclose(fp2);
  return 0;
}
void getinfo(double a[], int n, FILE *file1, FILE *file2)
{
  int i;
  do {
    for(i = 0; (i < n) && (a[i] != EOF); i++) {
      a[i] = fgetc(file1);
      fprintf(file2, "%g ", a[i]);
      printf("%g", a[i]);
    }
  } while (a[i] != EOF);
}

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Quote:

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if (argv[1] == "-t")

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This is not how you compare strings in C. You would probably want to include string.h and call strcmp to check for equality.

Also, as you seem to be programming in Linux you might want to search for examples using "getopt_long" which is built for handling command line switches.