A quick pointer question

My code is divided in two source files. One of the source files includes main, the other one some functions I wrote.

In the source file where main is, I declare the global variable

Code:

---

char hello[256];

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And pass it to a function defined in the other source file:

Code:

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void function(char *hello); // the prototype
function(hello);

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Quick question... will the function "function" work with the address of the global variable defined in the other source file, or will it receive a new copy of "hello" and work with that?

Thanks!

It's a pointer, so it's the same array.

OK thanks, I thought so, just had a small doubt.

another relative quick question.

the function on the other file is prototyped

Code:

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void function(char *hello);

---

but hello is also a global variable, won't it get mixed up since a local variable is named just like a global?

The local variable will "hide" the global variable.
The global variable will exist but is unaccessible due to the local variable hello.
This can be circumvented in C++, but not C.

ok thanks.

i'm learning C++ little by little at the same time I do a lot of stuff...
I don't know exactly how I could circumvent it, but I bet I need to use the scope operator :: right?

Code:

---

int a = 2;
void foo(int a)
{
        cout << a << endl;
        cout << ::a << endl;
}

int __cdecl _tmain(int /*argc*/, TCHAR* /*argv*/[], TCHAR*)
{
        foo(1);
}

---

Output:
1
2

cool, thanks