ternary operation with compound instruction

Hello guys.
By the specification of C I know i can use several instructions (with ) instead of use just one. But is it true if i´m using a ternary operation?
i.e.,

Code:

---

x > 10 ? printf( "x > 10\n" ) : printf( "x <= 10\n" ); //valid
x > 10 ? { printf( "x > 10" ); printf( "\n" ); } : { printf( "x <= 10" ); printf( "\n" ) };//question, something like this

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Can you help me (I know my example can be changed in a better way, but it´s just an example!)?

Thanks, Daniel.

I suppose you could use the comma operator, but you have to know that it only returns the value of the rightmost expression.

Code:

---

x > 10 ? printf( "x > 10" ), printf( "\n" ) : printf( "x <= 10" ), printf( "\n" );

---

Thanks, but it´s wrong. This way it returned the rightmost expression and returned both other expression inconditionally.

Someone else?

Thanks.

Well, may-be you'll need an extra set of parenthesis?

Code:

---

#include <stdio.h>
int main()
{
    int a = 5;
    int b = a > 4 ? (printf("More than 4\n"), 1) : (printf("Not more than 4\n"), 2);
    printf("&#37;d", b);
    return 0;
}

---

Anyway, it might be actually clearer as a if...else expression.

A passing thought on the matter:

Code:

---

#include <stdio.h>

void foo(int x, int y)
{
  printf("&#37;d %s %d\n", x, x < y ? "<" : ">=", y);
}

int main ()
{
  foo(5, 10);
  foo(15, 10);
    return 0;
}

/* my output
5 < 10
15 >= 10
*/

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thanks. it´s good! but it´s sounds strange, doesn´t? it might be

Code:

---

{ ... }

---

, hence "where there´s 1 instruction you can put 1 or more in that place."...

Thanks

Braces are for code blocks with their own scope. I don't believe any operator (including ?:) allows it's operands to be blocks of code.

But there is such a comma operator and it must have some use.