Arrays in functions

How would i use an array ( that is defined in the main() ) in a function? how would i define it?
for example:

Code:

---


void Function( int grid[4][4] );

int main()
{
    int array[4][4];
    Function(array[4][4]);
    return 0;
}

void Function( int grid[4][4] )
{
    printf("  %d  %d  %d  %d\n  %d  %d  %d  %d\n  %d  %d  %d  %d\n  %d  %d  %d  %d\n",  grid[0][0], grid[0][1], grid[0][2], grid[0][3], ... , grid[3][3]);
}

---

this is a watered down version of what im working on, but i need array[4][4] to equal grid[4][4], and all the numbers in the arrays to match up. is this even possible? or will i have to copy and paste the printf line throughout my code whenever it is needed?

You have it almost nailed down . . . you just need to call the function like this:

Code:

---

Function(array);

---

You see, Function takes a variable of type int [4][4]. "array" matches that type. But "array[4]" is of type int[4], and "array[4][4]" is of type int, never mind that both of those indices are out of bounds. :)

Thanks alot for the quick reply :D