input a string in gcc

following is the code to accept a string from user, but i get segmentation fault as soon i have finished entering a sentence i.e. as soon as i press the 'enter' key.

Code:

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#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main (void)
{
        char str[50];
        printf ("Enter string:\n");
        fgets (str, sizeof str, stdin);
        //further code
}

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if anybody can help me enter the string, thanx!

Is that the actual program you tried?

Or just something which you think looks like the program you tried?

Because as it stands, I can't see any reason why those 3 lines in a main() would cause a segfault.

So please post something which actually crashes.

I guessing it's the "further code" part

Well i didn't consider further code important because i had already
used a printf("test") statement immediately after fgets & it's not
getting executed. I get seg fault eror the instant i hit the enter
key.

Quote:

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Well i didn't consider further code important because i had already
used a printf("test") statement immediately after fgets & it's not
getting executed. I get seg fault eror the instant i hit the enter
key.

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That's interesting. Try the code below and see if you get a seg fault:

Code:

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#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void)
{
    char str[50];
    printf("Enter string:\n");
    fgets(str, sizeof str, stdin);
    printf("&#37;s\n", str);
    return 0;
}

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If you do not get a seg fault, then something else must be wrong with your original code, so you should post the smallest and simplest program that demonstrates the error.

Code:

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printf("test");

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Most likely wouldn't work, since you'd put it in the stdout buffer (which probably won't get flushed). Then you run the code that segfaults and it never gets flushed/printed. Bit like:

Code:

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enter string
put 'test' in the output buffer
segfault

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Change it to:

Code:

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printf("test\n");

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or

Code:

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printf("test");
fflush(stdout);

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