Open File

Hey,
I am making a program where the user is asked what filename he wants to open.

This is what I have:

cout<<"Enter File Name"<<endl;
cin>>filename;

ifstream inl(filename.txt);

What do I need?
Thanks

i could be wrong but i believe the ifstream constructor takes a c-string (char*). so you would have to have

Code:

---

cout<<"Enter File Name"<<endl;
cin>>filename;

ifstream inl(filename.c_str());

---

string::c_str() returns its c-string counterpart.

you are right... he can also do this

...

char str[30];

cout << "Filename";
cin >> str;

ifstream ins;

ins.open(str);

...


>>>ifstream inl(filename.txt);

oh... and the .txt part doesn't work like that. That wouldn't compile.

it would work if "txt" was a variable inside the structure "filename" but it isn't, so ya, it wouldn't compile.

When I first glanced I thought all you was trying to do was open a file named filename.txt.

Hey Thanks