How do I index into a List<Array>?

I want a dynamic multidimensional array of strings. I searched the forum a bit and it seems that a List<Array> is what I want to use. Here's an idea of what I'm doing:

Code:

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List<Array> timetrackview = new List<Array>();

//Get some rows from SQL and store results in:
String[] ttvData = new String[8];
//then add string array to timetrackview
timetrackview.Add(ttvData);

//since I know the second returned column is an int stored in my array I want to store it somewhere else
lastSR = int.Parse(timetrackview[0][1]);

//except this doesn't work

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I cannot use a foreach; any help would be appreciated.

it would be

Code:

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timetrackview[0].GetValue(1).ToString();

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or have a List<List<sometype>>;

You sir, are my hero. Thanks!

with a List<List<sometype>> you can have a dynamic array in both dimensions and use the two dimensional index operation and are better typed

Then there are beautiful things called extension methods. You put these public static methods in public static classes and mark the first parameter with the "this" keyword so any objec within it's scope looks at it as a member value. Example

Code:

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        public static class Extensions
        {
                public static int Get2d(this List<Array> x, i1, i2) //this indicates implicit parameter
                {
                        //bounds checking perhaps
                        return (int)x[i1].GetValue(i2);
                }
        }

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now you can call it as such

Code:

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tmp.Get2d(0, 1)

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See you're calling the Get2d method, but without passing the list as the first parameter, all List<Array>s sees it as a member method.

Now that's pretty slick. Luckily for me in this instance I only need the dynamicness of the list. Since I know that the array inside will always only need 8 cells. I'll try to remember this if I need a truly dynamic multidimensional array.

then why not have it a List<string[]>

I had tried that, but kept getting errors. This way I posted above worked fine for me.

perhaps you initialized it List<string[8]>?

I think what I'd tried was List<string[]>=new List<string[8]>(), but I don't remember for sure and that code is long gone now.