Need Help

I am trying to write a program that will tell whether or not to go to work based on the day of the week entered by the user. Here is what I have so far.

Code:

---

#include <stdio.h>
#define TRUE 1
#define FALSE 0

void dayofweek();

int main()
{       
        char today[100];
        int i;
       
        enum week {Monday = 0, Tuesday = 1, Wednesday = 2, Thursday = 3, Friday = 4, Saturday = 5, Sunday = 6};
       
        printf ("Enter the day of the week (eg. Wednesday) :\n");
        scanf ("%c", today[]);
       
        dayofweek (today);
       
        return 0;
}
        void dayofweek(char today[])
{
        if (today = 0; today < 5; today++)
        printf ("GO TO WORK!!");
       
                else
                printf("You can rest today");
}

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so.... what's the problem? I realized that you're trying to input a string as a char though

Code:

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scanf ("%c", today[]);

---

Even if you wanted to correct that to read a string, you'd need to take the two square brackets away.
Also, your if statement's syntax is totally wrong. You're obviously mixed up between if and for.
Assuming you want to input the day of the week as a number (that's what I understand from your enum), you'd need your if to look like this:

Code:

---

if (today >=0 && today <= 5)
    printf("GO TO WORK!!!");
else
    printf("You can rest today");

---

Quote:

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Originally Posted by Abda92

Code:

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if (today >=0 && today <= 5)

---

---

work on Saturday?
yuk :/

sorry, I just based it on his logic.
it should be <= 4

Okay. Here is what I have now. I am getting a parse error before ";" token on line 36.

I am trying to enter the day of the week ie. Monday and get the results to return as GO TO WORK or you can stay home.

Code:

---

#include <stdio.h>

void dayofweek();

int main()
{       
       
        char today[100];
        int i;
       
        enum week {Monday = 0, Tuesday = 1, Wednesday = 2, Thursday = 3, Friday = 4, Saturday = 5, Sunday = 6};
       
        printf ("Enter the day of the week (eg. Wednesday) :\n");
       
        scanf ("%s", today);
       
        dayofweek (today);
       
        return 0;
       
}

        void dayofweek(strng)
       
{
        int i;
       
        if (i >= 0; i < 5)
        printf ("GO TO WORK!!");
       
        else
        printf("You can rest today");
       
}

---

Now I get a successful build but the results always return as You can rest today.

Code:

---

#include <stdio.h>

void dayofweek();

int main()
{       
       
        char today[100];
        int i;
       
        enum week {Monday = 0, Tuesday = 1, Wednesday = 2, Thursday = 3, Friday = 4, Saturday = 5, Sunday = 6};
       
        printf ("Enter the day of the week (eg. Wednesday) :\n");
       
        scanf ("%s", today);
       
        dayofweek (today);
       
        return 0;
       
}

        void dayofweek(strng)
       
{
        char today;
       
        if (today >= 0 && today <= 4)
        printf("GO TO WORK!!");
       
        else
        printf("You can rest today");
       
}

---

Two questions:

1) Are enumerated values char's or int's? You have today as a char in days of week()

2) When you print the value of "today" in days of week(), what do you see?

I thought enum values could be char. I could be wrong, I am new to c prog.

Also, no matter what I put is as the user response, I get the same results "You can rest today"

Now this is were I am at. Still getting the same results regardless of user entry.

Code:

---

#include <stdio.h>
#include <string.h>
void dayofweek();

int main()
{       
        char today[15];
       
        printf ("Enter the day of the week (eg. Wednesday) :\n");
       
        scanf ("&#37;c", &today);
       
        enum week {Saturday = 0, Sunday = 0, Monday = 1, Tuesday, Wednesday, Thursday, Friday};
       
        int i = *today;
       
        dayofweek (*today);

        return 0;
       
}

        void dayofweek(int *today)
       
{
        int i;
       
        if (i != 0)
        printf("GO TO WORK!!");
       
        if (i = 0)
        printf("You can rest today");
       
}

---

Quote:

---

Originally Posted by jhp1025

Now this is were I am at. Still getting the same results regardless of user entry.

Code:

---

#include <stdio.h>
#include <string.h>
void dayofweek();

int main()
{       
        char today[15];
       
        printf ("Enter the day of the week (eg. Wednesday) :\n");
       
        scanf ("%c", &today);
       
        enum week {Saturday = 0, Sunday = 0, Monday = 1, Tuesday, Wednesday, Thursday, Friday};
       
        int i = *today;
       
        dayofweek (*today);

        return 0;
       
}

        void dayofweek(int *today)
       
{
        int i;
       
        if (i != 0)
        printf("GO TO WORK!!");
       
        if (i = 0)
        printf("You can rest today");
       
}

---

---

Tell me - how do you logically justify passing a value to a function, but not using it in the function?

You need to pass the value to the function, and then check that value.

Well, I haven't tested this, but from what you just posted I can give you a few pointers.

Your function prototype at the top does not match the actual function that you have made. You need to put the arguments in the prototype that you also have in your function.

In your main function, you call your dayofweek() function with *today, but that datatype doesn't match what you have declared for your function argument, int *. You most likely will get a warning for this.

This is where im at now. Same results for anything entered as user. Stil GO TO WORK for anythinmg entered.

Code:

---


#include <stdio.h>
#include <string.h>

#define LSIZE 15
void week();

int main()
{       
        char today[LSIZE];

        enum week {Saturday = 0, Sunday = 0, Monday = 1, Tuesday, Wednesday, Thursday, Friday};

        printf ("Enter the day of the week (eg. Wednesday) :\n");

        week (today);
       
        sscanf ("&#37;s", today);

        if (today == 0)
        printf("You can rest today");
       
        if (today != 0)
        printf("GO TO WORK!!");
       
        return 0;
       
}

        void week(char strng[])
       
{       
        int i =0;
        char c;
       
        while (i < (LSIZE-1) && (c = getchar()) !='\n')
       
        {
                strng[i] = c;
                i++;
        }
       
        strng[i] = '\0';
               
}

---

You do realize you compare a pointer to a string (that's what today is) with 0? You need to compare the string that is input with the strings "Monday", "Tuesday", etc.

And that sscanf shouldn't compile.

Im not following

Just defining the enum doesn't do any of the work in comparing what's typed in to the names of the days. You'll have to do it yourself.