Displaying 'double' type variables using 'cout' - upto 15 decimal places

Hi,

I want to display uptill the 15th decimal place the value of a double type variable using cout.

When I use:

Code:

---

cout << x << endl;

---

It just gives me the first 4 decimal places.

Thanks a lot in advance.

std::setprecision

Thanks a lot.

Or, cout.precision(15) ;