foo

i am trying to run the following program and i keep getting a compiling error that says that foo is not a function. What am I doing wrong?

Code:

---


#include <stdio.h>
#include <stdlib.h>

double* makeAnArray(double size);
       
int main (void)
        {
        double *anArray;
        int size=0;
        int i;
        double *foo;

        printf("Please enter the size of the array  ");
        scanf("%d", &size);

        anArray=makeAnArray(size);

for (i = 0; i < size; i++)
        {
                printf("%.1f  ", anArray[i]);
        }
        printf("\n");

foo(anArray,size);

        free(anArray);

        getchar();
return 0;       
}
double* makeAnArray(double size){
        double* array;
        array =calloc(size,sizeof(double));
        return array;
}

void foo (double* a, double size){
        int i;
        for (i=0; i<size; i++){
                *(a+i)=132;
        }
}

---

You need to prototype foo so you can use it.

A few other things,
* Don't use double for everything
* calloc() expects size_t as arg1 not a double
* Check the return value of calloc()
* Learn how to indent.

i got the prototype down and i indented, and I am trying to figure out why it still tells me that foo is not a function?

Code:

---


#include <stdio.h>
#include <stdlib.h>

double* makeAnArray(double size);
void foo(double*a, double size);
int main (void)
{
        double *anArray;
        int size=0;
        int i;
        double *foo;

        printf("Please enter the size of the array  ");
        scanf("&#37;d", &size);

        anArray=makeAnArray(size);

        for (i = 0; i < size; i++)
        {
                printf("%.1f  ", anArray[i]);
        }
        printf("\n");

        foo(anArray,size);

        free(anArray);

        getchar();
        return 0;       
}
double* makeAnArray(double size){
        double* array;
        array =calloc(size,sizeof(double));
        return array;
}

void foo (double* a, double size){
        int i;
        for (i=0; i<size; i++){
                *(a+i)=132;
        }
}

---

You're defining a local variable "double *foo"

i am sorry to keep bothering you but i am very new to this whole programing thing.
do i use void instead of double*

delete this line. u prototyped foo already. change the prototype to double instead of void if u want a return type double.

Code:

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        double *foo;

---

The red bits are the areas of interest:

Code:

---

#include <stdio.h>
#include <stdlib.h>

double* makeAnArray(double size);
void foo(double*a, double size);
int main (void)
{
    double *anArray;
    int size=0;
    int i;
    double * foo;

    printf("Please enter the size of the array  ");
    scanf("&#37;d", &size);

    anArray=makeAnArray(size);

    for (i = 0; i < size; i++)
    {
        printf("%.1f  ", anArray[i]);
    }
    printf("\n");

    foo(anArray,size);

    free(anArray);

    getchar();
    return 0;   
}
double* makeAnArray(double size){
    double* array;
    array =calloc(size,sizeof(double));
    return array;
}

void foo (double* a, double size){
    int i;
    for (i=0; i<size; i++){
        *(a+i)=132;
    }
}

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