Trouble with IFs

Rather than having to input :

If (number= (100*1)+10){
printf("number times a hundred plus ten");

If(number=(100*1)+10){
printf("number times a hundred plus ten");

etc...

Isn't there a way i can condense that into one IF with an Or ||... i've tired it but what ends up happening is any number sent to this subroutine prints the message even though i only want it to print if it specifically meets ((100*1)+10) or ((100*2)+10) etc.

What am i doing wrong ?

Please and thank you :).

= is assignment
== is comparison

Oops, my mistake i meant ==, but yeh even then the problem occurs. Cant i set multiple parameters in a single IF ? If so, how ?

Please post your ACTUAL code, not paraphrased code.

--
Mats

If (number= =(100*1)+10){
printf("number times a hundred plus ten");

If(number==(100*1)+10){
printf("number times a hundred plus ten");


Although paraphrased this is essentially the exact same, all i want to know is if i can convert the two IFs above into just one.


If (number= =(100*1)+10) AND HAVE THIS IN HERE TOO (number==(100*1)+10){
printf("number times a hundred plus ten");

They test the same condition, so you could write:

Code:

---

if (number == (100*1)+10) {
    printf("number times a hundred plus ten");
    printf("number times a hundred plus ten");
}

---

If they were different, you could join them with an || (or).

Code:

---

if (condition1)
    if (condition2)
        some_code;

---

Is the same as

Code:

---

if (condition1 && condition2)
    some_code;

---

If condition1 AND condition2
It's also possible to do:

Code:

---

if (condition1 || condition2)
    some_code;

---

If condition1 OR condition 2.