Help me to this please I'm begging..

this are my programs that I made before and as a project my teacher asked me to recode all my programs and compress it in one program with menu.. I was absent that time when my teacher discuss about "case" because I have asthma and I was confined at the hospital.. my teacher said to self study but its so hard for me to understand it without someone explaining it to me... so please someone help me to put all this program in MENU??

Help me... dead line tomorrow so that I'm so scared, I'm so helpless and hopeless on how to do this...

my teacher said to me that I can use any technique or code, but the important is its in the MENU...

Please..... a deep thankful to everyone who can help me and give me some advice..
good thing this kind of website is existing.. Thank you very much!!! God Bless...


SORRY for disturbing you guys... sorry for some wrong grammars there...
THANK YOU!!! =,)

Code:

---

Program1
#include <stdio.h>
#include <conio.h>
void main()
{
float ar[10]={1.1};
double ray[10]={9.29};
float *x;
double *y;
int a;
clrscr();
x=&ar[0];
y=&ray[0];

  printf("\nthe value of float is: %.2f",*x++);
  printf("\n");
  printf("\nthe value of double is: %.2lf",*y++);

getch();
}


Program2
#include<stdio.h>
#include<conio.h>

void floating(float arr[],float *ave, float *sum)
{
float a,b;
int ctr;
for(ctr=0;ctr<=10;ctr++)
{
 a+=arr[ctr];
}
 b=a/10;
 *sum=a;
 *ave=b;
}

void main()
{
float arr[10]={1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0};
float sum;
float ave;
int ctr;
clrscr();
for(ctr=0;ctr<=10;ctr++);
{
arr[ctr];
}
  floating( arr,&ave,&sum );

printf("\n the average is : %.2f",ave);
printf("\n the sum is : %.2f",sum);
getch();
}


Program3
#include<stdio.h>
#include<conio.h>
void main()
{
float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
float *pf;
int ctr;
clrscr();
for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[0];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array first to the last: %.1f",*pf++);
}
getch();
}



Program4
#include<stdio.h>
#include<conio.h>
void main()
{
double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
double *pf;
int ctr;
clrscr();
for(ctr=0;ctr<=9;ctr++)
{
 printf("\nthe array list [%d]: %.2lf",ctr, arr[ctr]);
}
printf("\n");

        pf=&arr[0];
    for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array first to the last: %lf",*pf++);
      }

getch();
}


Program5
#include<stdio.h>
#include<conio.h>
void main()
{
float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
float *pf;
int ctr;
clrscr();
for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[9];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array last to first: %.1f",*pf--);
}
getch();
}



Program6
#include<stdio.h>
#include<conio.h>
void main()
{
double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
double *pf;
int ctr;
clrscr();
for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2lf",ctr , arr[ctr]);
}

printf("\n");

          pf=&arr[9];
      for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array last to first: %.2lf",*pf--);
      }
getch();
}

---

Well, let's start by merging this. Do you understand how to create and manage a menu?

Turn each main() function into its own function.

Inside your new main() function, create the menu using printf(). Allow the user to input his choice from the displayed menu. Read that input in using scanf(). Run a switch statement on the input character. If 1, go function 1. If 2, do function 2.

Code:

---

switch (input_char)
{
          case 1:
                      function1();
                      break;
          case 2:
                      function2();
                      break;
          /* ... */
          default:
                      break;
}

---

sorry ma'am but I don't know how to start.. and I don't know how to separate those functions and those variables...

I tried

Code:

---

if (option==1)
printf("******");

else if (option==2)
printf("********");

else if(option==3)
exit();
else
go to ct;

---

I tried that program but too much errors... I got 25 errors... and its all because of declaring a variable is not allowed..
like this...

Code:

---

#include <stdio.h>
#include <conio.h>
void main()
{
float ar[10]={1.1};
double ray[10]={9.29};
float *x;
double *y;
int a;
x=&ar[0];
y=&ray[0];
float a,b;
int ctr;
float arr[10]={1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0};
float sum;
float ave;
float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
float *pf;
double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
double *pf;
float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
float *pf;
double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
double *pf;

int ctr;


ct:
printf("Main Menu\n");
printf("\n\n1)Program that declares one float variable and one double data type variable");
printf("\n 2)");
printf("\n 3)");
printf("\n 4)Compute the sum and average of the elements of the array");
printf("\n 5)Initialize the array, set a pointer that points to the first, and print all the elements of the array from the first down to the last");
printf("\n 6)Double data type accessing the array elements");
printf("\n 7)Initialize the array, set a pointer that points to the last, and print all the elements of the array from the first down to the last");
printf("\n 8)with 10 double data type elements");
printf("\n 9)Exit");
printf("Enter your choice");
scanf("%d",&option);
if(option==1)


  printf("\nthe value of float is: %.2f",*x++);
  printf("\n");
  printf("\nthe value of double is: %.2lf",*y++);


else if(option==2)


void floating(float arr[],float *ave, float *sum)
{

for(ctr=0;ctr<=10;ctr++)
{
 a+=arr[ctr];
}
 b=a/10;
 *sum=a;
 *ave=b;
}


{

for(ctr=0;ctr<=10;ctr++);
{
arr[ctr];
}
  floating( arr,&ave,&sum );

printf("\n the average is : %.2f",ave);
printf("\n the sum is : %.2f",sum);


else if(option==3)

{


for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[0];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array first to the last: %.1f",*pf++);
}

else if(option==4)

{

for(ctr=0;ctr<=9;ctr++)
{
 printf("\nthe array list [%d]: %.2lf",ctr, arr[ctr]);
}
printf("\n");

        pf=&arr[0];
    for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array first to the last: %lf",*pf++);
      }


else if(option==5



for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[9];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array last to first: %.1f",*pf--);
}


else if(option==6)


for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2lf",ctr , arr[ctr]);
}

printf("\n");

          pf=&arr[9];
      for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array last to first: %.2lf",*pf--);
     

else if(option==7)
exit();
else
go to ct;
}

---

I know its crazy but I don't have any option.. I got mental blocked.. ='(

You didn't define option anywhere.

Code:

---

int option;

---

In some of your functions, it seems like you're defining and initializing arr, and then using a for loop two steps later to overwrite everything you initialized. Unfortunately, your statement isn't even doing that correctly. This statement has no effect:

Code:

---

        for(ctr=0;ctr<10;ctr++);
        {
                arr[ctr];
        }

---

You're also going to run into some buffer overrun problems using your for loop. You shouldn't be checking ctr <= 10. You should be checking ctr < 10, if you start ctr at 0.

Code:

---

void floating(float arr[],float *ave, float *sum)
{
        float a,b;
        int ctr;
        for(ctr=0;ctr<10;ctr++)
        {
                a+=arr[ctr];
        }
        b=a/10;
        *sum=a;
        *ave=b;
}

---

so I have to specify each and change their variable name??? yes I already Initialize option but their still an error: declaration on variable not allowed..

sir each of my programs has no error.. the error is when I recode it into MENU... ahhh.... I'm so idiot.... I don't know how to deal with this... aarrrghhh..... anyway so many thanks to you sir... sorry because I wasted your... Thanks a lot god bless

Since it is a C program,
1)Declarations should come first.
2)Multiple declarations are not allowed in C.
u have declared variables twice.try deleting any one of them.
3)instead of using goto try a while(1) loop
And finally don't paste the function definition and paste only the code inside it.
Hope it helps.

When you are combining different source files, it's not just a case of "copy and paste and re-arrange the lines" - you need to make more changes than that.

For example, you now have several variables all called "arr", "sum" and "pf" (for example). In some cases, you even have differing types.

Where the variables are identical (both type, name and content), you could just remove the duplicates.

In case where you have different types or values (content), you will need to change the name.

You are defining a function inside main:

Code:

---

void floating(float arr[],float *ave, float *sum)
{

for(ctr=0;ctr<=10;ctr++)
{
 a+=arr[ctr];
}
 b=a/10;
 *sum=a;
 *ave=b;
}

---

This is not valid C, each function must be defined outside any other function.

--
Mats

thanks with you too... I'll try to recode this till death, until it run

Quote:

---

Originally Posted by lesrhac03

sir each of my programs has no error.. the error is when I recode it into MENU... ahhh.... I'm so idiot.... I don't know how to deal with this... aarrrghhh..... anyway so many thanks to you sir... sorry because I wasted your... Thanks a lot god bless

---

I wouldn't give up. We're almost there.

Can you give me the line of code that your error is occuring on? I've got a compiled program here that I'm working with.

Quote:

---

Originally Posted by lesrhac03

thanks with you too... I'll try to recode this till death, until it run

---

Make sure you UNDERSTAND what you are changing - if you just randomly change it, you will NOT make it run. If you don't understand what the change does, ask...

--
Mats

Hey I have cleared syntax errors in ur program.
Dont blame me if they have logical errors.
I havent looked upon them :).
And I haven't indented them too.

Code:

---

#include <stdio.h>
#include <conio.h>
void main()
{
float ar[10]={1.1};
double ray[10]={9.29};
float *x;
double *y;
float a,b;
int ctr;
float sum;
float ave;
float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
float *pf;
int option;



x=&ar[0];
y=&ray[0];

while(1){                                                        //don't use goto
printf("Main Menu\n");
printf("\n\n1)Program that declares one float variable and one double data type variable");
printf("\n 2)");
printf("\n 3)");
printf("\n 4)Compute the sum and average of the elements of the array");
printf("\n 5)Initialize the array, set a pointer that points to the first, and print all the elements of the array from the first down to the last");
printf("\n 6)Double data type accessing the array elements");
printf("\n 7)Initialize the array, set a pointer that points to the last, and print all the elements of the array from the first down to the last");
printf("\n 8)with 10 double data type elements");
printf("\n 9)Exit");
printf("Enter your choice");
scanf("&#37;d",&option);
if(option==1){


  printf("\nthe value of float is: %.2f",*x++);
  printf("\n");
  printf("\nthe value of double is: %.2lf",*y++);
}

else if(option==2){
for(ctr=0;ctr<=10;ctr++)
{
 a+=arr[ctr];
}
 b=a/10;
 sum=a;
 ave=b;
/*for(ctr=0;ctr<=10;ctr++);
{
arr[ctr];                                        //??????
} */
printf("\n the average is : %.2f",ave);
printf("\n the sum is : %.2f",sum);
}

else if(option==3)

{


for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[0];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array first to the last: %.1f",*pf++);
}
}
else if(option==4)

{

for(ctr=0;ctr<=9;ctr++)
{
 printf("\nthe array list [%d]: %.2lf",ctr, arr[ctr]);
}
printf("\n");

        pf=&arr[0];
    for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array first to the last: %lf",*pf++);
      }

 }
else if(option==5){



for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
}
printf("\n");
    pf=&arr[9];
for(ctr=0;ctr<=9;ctr++)
{
  printf("\n elemnts of the array last to first: %.1f",*pf--);
}
}

else if(option==6)
{
for(ctr=0;ctr<=9;ctr++)
{
  printf("\nthe array list [%d]: %.2lf",ctr , arr[ctr]);
}

printf("\n");

          pf=&arr[9];
      for(ctr=0;ctr<=9;ctr++)
      {
        printf("\n elemnts of the array last to first: %.2lf",*pf--);

}
}
else
exit();
}
}

---

It's one big mess when not indented:

Code:

---

#include <stdio.h>
#include <conio.h>
void main()
{
        float ar[10]={1.1};
        double ray[10]={9.29};
        float *x;
        double *y;
        float a,b;
        int ctr;
        float sum;
        float ave;
        float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
        float *pf;
        int option;



        x=&ar[0];
        y=&ray[0];

        while(1){                                                        //don't use goto
                printf("Main Menu\n");
                printf("\n\n1)Program that declares one float variable and one double data type variable");
                printf("\n 2)");
                printf("\n 3)");
                printf("\n 4)Compute the sum and average of the elements of the array");
                printf("\n 5)Initialize the array, set a pointer that points to the first, and print all the elements of the array from the first down to the last");
                printf("\n 6)Double data type accessing the array elements");
                printf("\n 7)Initialize the array, set a pointer that points to the last, and print all the elements of the array from the first down to the last");
                printf("\n 8)with 10 double data type elements");
                printf("\n 9)Exit");
                printf("Enter your choice");
                scanf("%d",&option);
                if(option==1){


                        printf("\nthe value of float is: %.2f",*x++);
                        printf("\n");
                        printf("\nthe value of double is: %.2lf",*y++);
                }

                else if(option==2){
                        for(ctr=0;ctr<=10;ctr++)
                        {
                                a+=arr[ctr];
                        }
                        b=a/10;
                        sum=a;
                        ave=b;
                        /*for(ctr=0;ctr<=10;ctr++);
                        {
                        arr[ctr];                                        //??????
                        } */
                        printf("\n the average is : %.2f",ave);
                        printf("\n the sum is : %.2f",sum);
                }

                else if(option==3)

                {


                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
                        }
                        printf("\n");
                        pf=&arr[0];
                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\n elemnts of the array first to the last: %.1f",*pf++);
                        }
                }
                else if(option==4)

                {

                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\nthe array list [%d]: %.2lf",ctr, arr[ctr]);
                        }
                        printf("\n");

                        pf=&arr[0];
                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\n elemnts of the array first to the last: %lf",*pf++);
                        }

                }
                else if(option==5){



                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
                        }
                        printf("\n");
                        pf=&arr[9];
                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\n elemnts of the array last to first: %.1f",*pf--);
                        }
                }

                else if(option==6)
                {
                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\nthe array list [%d]: %.2lf",ctr , arr[ctr]);
                        }

                        printf("\n");

                        pf=&arr[9];
                        for(ctr=0;ctr<=9;ctr++)
                        {
                                printf("\n elemnts of the array last to first: %.2lf",*pf--);

                        }
                }
                else
                        exit();
        }
}

---

Let's make sure it works before suggesting trivial changes that needs to be made.

The one I put together uses a switch statement as requested.

And it's not one huge clusterf***.

Code:

---

#include <stdio.h>
#include <conio.h>

void function_one();
void function_two();
void function_three();
void function_four();
void function_five();
void function_six();
void floating(float arr[],float *ave, float *sum);

int main(void)
{
        int user_choice;
        char throwaway;
       
        while(1)
        {
                /** Create menu. */
                printf("Here are your choices:\n");
                printf("*** Enter 1 for function_one.\n");
                printf("*** Enter 2 for function_two.\n");
                printf("*** Enter 3 for function_three.\n");
                printf("*** Enter 4 for function_four.\n");
                printf("*** Enter 5 for function_five.\n");
                printf("*** Enter 6 for function_six.\n");
                printf("*** Enter 7 to EXIT!\n");
                printf("-----------------------------------\n");
                printf("Enter your choice now 1 - 6:");
                fflush(stdout);
                scanf("%d", &user_choice);
               
                /** Switch statement on user choice. */
                switch(user_choice)
                {
                        case 1:
                                printf("Function_one EXECUTING!\n");
                                function_one();
                                break;
                        case 2:
                                function_two();
                                break;
                        case 3:
                                function_three();
                                break;
                        case 4:
                                function_four();
                                break;
                        case 5:
                                function_five();
                                break;
                        case 6:
                                function_six();
                                break;
                        case 7:
                                printf("Exiting! Press ENTER to exit!\n");
                                fflush(stdout);
                                scanf("%c", &throwaway);
                                return 0;
                        default:
                                printf("You've entered an incorrect choice.\n");
                                fflush(stdout);
                                break;
                }
        }
       
        return 0;
}

void function_one()
{
        float ar[10]={1.1};
        double ray[10]={9.29};
        float *x;
        double *y;

       
        x=&ar[0];
        y=&ray[0];

        printf("\nthe value of float is: %.2f",*x++);
        printf("\n");
        printf("\nthe value of double is: %.2lf",*y++);
}


void floating(float arr[],float *ave, float *sum)
{
        float a,b;
        int ctr;
        for(ctr=0;ctr<10;ctr++)
        {
                a+=arr[ctr];
        }
        b=a/10;
        *sum=a;
        *ave=b;
}

void function_two()
{
        float arr[10]={1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0};
        float sum;
        float ave;
       
        floating( arr,&ave,&sum );

        printf("\n the average is : %.2f",ave);
        printf("\n the sum is : %.2f",sum);
}


void function_three()
{
        float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
        float *pf;
        int ctr;

        for(ctr=0;ctr<10;ctr++)
        {
                printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
        }
        printf("\n");
        pf=&arr[0];
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\n elemnts of the array first to the last: %.1f",*pf++);
        }
}




void function_four()
{
        double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
        double *pf;
        int ctr;

        for(ctr=0;ctr<10;ctr++)
        {
                printf("\nthe array list [%d]: %.2lf",ctr, arr[ctr]);
        }
        printf("\n");

        pf=&arr[0];
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\n elemnts of the array first to the last: %lf",*pf++);
        }
}


void function_five()
{
        float arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
        float *pf;
        int ctr;
       
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\nthe array list [%d]: %.2f",ctr , arr[ctr]);
        }
       
        printf("\n");
       
        pf=&arr[9];
       
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\n elemnts of the array last to first: %.1f",*pf--);
        }
}


void function_six()
{
        double arr[10]={1.1,1.2,1.3,1.4,1.5,1.6,1.7,1.8,1.9,2.0};
        double *pf;
        int ctr;
       
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\nthe array list [%d]: %.2lf",ctr , arr[ctr]);
        }

        printf("\n");

        pf=&arr[9];
       
        for(ctr=0;ctr<10;ctr++)
        {
                printf("\n elemnts of the array last to first: %.2lf",*pf--);
        }
}

---

Unfortunately, despite what you say, some of your functions do have errors in them. Best of luck.

wow. How did you indent that so fast?
Is there any software to indent already existing programs?

And at least option == 6 is now broken, because it uses arr[] which is of type float, not double [and the format specifier is %lf, which is used for "long double", so in some compilers it will print incorrect data].


--
Mats

Quote:

---

Originally Posted by stevesmithx

wow. How did you indent that so fast?
Is there any software to indent already existing programs?

---

Visual studio, Dev-C++, Emacs and many others can indent code for you.

--
Mats

Quote:

---

Originally Posted by stevesmithx

wow. How did you indent that so fast?
Is there any software to indent already existing programs?

---

I simply pasted it into Visual Studio with Visual Assist X installed and the copied it back and pasted it here.
Otherwise it's also possible to select all the code and press Alt+F8 to indent it all.

Quote:

---

Originally Posted by matsp

Visual studio, Dev-C++, Emacs and many others can indent code for you.

--
Mats

---

Eclipse also has a "Correct Indentation" function, as does VisualSlickEdit (Beautify Source).

Quote:

---

Originally Posted by JDGATX

Eclipse also has a "Correct Indentation" function, as does VisualSlickEdit (Beautify Source).

---

Yes, that would come under "many others". We could probably spend the rest of the year enumerating ALL editors that have this capacity.

--
Mats

Thanks for that tip everyone.
I needed one such s/w for so many months.

Thank you for all of your HELP!!! thank so much guys... thanks.... GOD BLESS all of you...

your a legend.. so many thanks..!