round and abs in c++

looking for this equivalent functions in c++

in pascal you just write round x or abs x and outputs what u want

im searching like half an hour the msdn found something for abs but its of type int abs( int n );

I'm not sure bout rounding but for abs:

#include <math.h>
#include <iostream.h>
#include <stdlib.h>

int main() {

int number = -5;

cout << abs(number);

system("PAUSE");
return 0;
}

There is ceil() and floor(); and setprecision(); and of course truncation, but I don't know of a standard rounding function. I've seen some 3rd party versions that don't look to tough to write, so give a shot yourself and see what you come up with

isnt that weird a whole prog. language like c++ doesnt have a
predifined function for round

anyways ill try something out
hehehe

to round to nearest int....

int Round( double in)
{
return (floor (in+0.5));
}

int rounding( float y,float yaxis)
{
double a;
char &buffer;
int decimal,sign;

a = (y+10)/yaxis;
buffer = _fcvt( a, 0 , &decimal , &sign );

return buffer;

};

well after doing some research in the msdn i found this and modified and made this function
but i get an error
cannot convert from 'char *' to 'char'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast
Error executing cl.exe.

ok boys i managed thx to the last guy for the help

int round(float y, float yaxis)
{
double in;
in = (y+10)/yaxis;

return (floor (in+0.5));

};