3 small char problems

hi guys I am having a bit of trouble with chars my problem is as follows:

c. (No prompts or explanatory text necessary.) The user types a 3-digit number which you input as 3 separate chars. You then compute the number that represents and output it as a single value. A sample run of your program might go as
540
540
The first line represents 3 char inputs that you do, and the second line represents one unsigned (or int) output that you do.

d. Same as c, except this time you do a single input of an unsigned (or int) and three char outputs. An example run of your program might go as
540
540

e. (Still no prompts or explanatory text necessary.) The input (you may assume without checking) is 2 chars: an upper case letter followed by a lower case letter. The output is the letters in reverse order, but the first letter output is to be uppercase and the second letter output is to be upper case. A sample run of your program might go as
Au
Ua


This is my code so far note my professor wanted us to do all 9 programs in 1 .cpp file thus the obnoxious large code.

Code:

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//  CS 575 HW 3


#include <iostream>
#include <string>
using namespace std;


void a();
void b();
void c();
void d();
void e();
void f();
void g();
void h();


bool die( const string & msg );


int main(){


/*
    unsigned n;
    cout <<"Gimme a # in [13,19]: ";
    cin >>n;
    if( !cin )  die( "C'mon, man, that's not even a number!" );
    if( n < 13 )  die( "too small" );
    if( n > 19 )  die( "too large" );


    cout <<"Thanks for the " <<n <<endl;
    cout <<"Thanks for using this amazing program" <<endl;
*/
    a();
    b();
    c();
    d();
    e();
    f();
    g();
    h();


}


void a(){
    unsigned dollars, quarters, dimes, nickels, pennies;
    cin >>dollars >>quarters >>dimes >>nickels >>pennies;
    cout <<100*dollars+25*quarters+10*dimes+5*nickels+pennies <<endl;
}    //  a


void b(){
    unsigned n;
    cin >>n;
    if( !cin )  die( "non-numeric input" );
    if( n < 10000 ) die( "too small" );
    if( n > 99999 ) die( "too large" );
    cout <<n/100 <<endl;
}    //  b


void c(){
    char n[3];
    cin >>n;
    cout<< n << endl;
}    //  c


void d(){
}    //  d


void e(){
}    //  e


void f(){
    string phoneNo;
    cin >>phoneNo;
    if( phoneNo.size() == 13                  &&
        phoneNo[0] == '('                      &&
        '2' <= phoneNo[1] && phoneNo[1] <= '9' &&
        '0' <= phoneNo[2] && phoneNo[2] <= '9' &&
        phoneNo[8] == '-' )
        cout <<"ok" <<endl;
    else
        cout <<"bogus" <<endl;
}    //  f


void g(){
    unsigned c0, c1;
    cin >>c0 >>c1;
    if( !cin )  die( "non-numeric input" );
    if( c0 < 1 || c0 > 13 || c1 < 1 || c1 > 13 )  die( "out of range" );
    if( c0 == c1 )
        cout <<"pair" <<endl;
    else
        cout <<"nothing" <<endl;
}    //  g


void h(){
}    //  h




bool die( const string & msg ){
    cerr <<endl <<"Fatal error: " <<msg <<endl;
    exit( EXIT_FAILURE );
}  //  d

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in problem in c I am stuck the compiler sends me an error e #2 stack around the variable "n" was corrupted. do i need if and elste statements? I was thinking of char to int conversion but its too confusing as I am still amateur.

Please understand I am still beginner thus your wisdom shall save me from my igorance. I will keep updating as I find solutions to my homework maybe it helps others as well.

Thanks for your time.

What are you inputting for the variables? Also I would comment out any of the functions that you have working and just work on one function at a time. When you use a C-string do not forget that you need to leave space for the end of string character ('\0') so if you need to input 3 characters into a C-string then the size of that C-string must be at least 4.

Also you should be using more descriptive variable and function names.

Jim

Quote:

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Originally Posted by elpedoloco

in problem in c I am stuck the compiler sends me an error e #2 stack around the variable "n" was corrupted. do i need if and elste statements? I was thinking of char to int conversion but its too confusing as I am still amateur.

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Problem 1: You cannot use cin to input into a char array.
Problem 2: You did not read your homework assignment. It clearly says to input them as 3 separate characters. Assuming you did not learn about std::getline yet, this tells me you should simple have 3 char declarations and input that way.
Problem 3: Are you suppose to validate your input until you get a good entry? Or just quit like you have been doing?

Quote:

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Originally Posted by elpedoloco

Please understand I am still beginner thus your wisdom shall save me from my igorance. I will keep updating as I find solutions to my homework maybe it helps others as well.

Thanks for your time.

---

You should take a look through the first couple of our C++ Made Easy Tutorials. That may help you with this assignment.

Quote:

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Problem 1: You cannot use cin to input into a char array.

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You can use cin to input values into a char array.

However I do agree that the assignment does seem to prohibit the use of C-strings.

Jim

Quote:

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Originally Posted by jimblumberg

You can use cin to input values into a char array.

However I do agree that the assignment does seem to prohibit the use of C-strings.

Jim

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Ok, my friend, for the pedantic yes you can; however as noted above it is a bad idea due to lack of bounds checking. The equivalent would be using gets() in C. Yes it works, but should you?

Quote:

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Originally Posted by AndrewHunter

Ok, my friend, for the pedantic yes you can; however as noted above it is a bad idea due to lack of bounds checking.

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Not really, e.g.,

Code:

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char str[10];
std::cin >> std::setw(10) >> str;

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Quote:

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Originally Posted by laserlight

Not really, e.g.,

Code:

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char str[10];
std::cin >> std::setw(10) >> str;

---

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And for the extremely pedantic, Hello Laser :tongue:, yes. However I doubt our friend the OP would know of / allowed to use such constructs. Additionally, things such as this only serve to obscure the problem at hand.

Quote:

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Originally Posted by AndrewHunter

And for the extremely pedantic, Hello Laser :tongue:, yes. However I doubt our friend the OP would know of / allowed to use such constructs. Additionally, things such as this only serve to obscure the problem at hand.

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hello thanks for the insight in my issue guys I've succesfully done part c which took me a few since I am a bit slow :P
but ether way I just want to make sure I am doing it right. here is my code which compiles successfully.

Code:

---


//  CS 575 HW 3


#include <iostream>
#include <string>
using namespace std;




void c();
void d();
void e();
void f();
void g();
void h();


bool die( const string & msg );


int main(){




    c();
    d();
    e();
    f();
    g();
    h();


}






void c(){
        char digits[4];
        cin.getline(digits, 4);
        cout << digits << endl; // why when I input digits[3] it will                            //only output 2?
               
}    //  c


void d(){
}    //  d


void e(){
}    //  e


void f(){
 
}    //  f


void g(){
 
}    //  g


void h(){
}    //  h




bool die( const string & msg ){
    cerr <<endl <<"Fatal error: " <<msg <<endl;
    exit( EXIT_FAILURE );
}  //  die

---

I had a few questions regarding my assigment, the first line represents 3 char imputs so 3 numbers but valued as chars?
second line represents one unsigned or (int) output that you do.
so I need a line on my code that has unsigned int? or is my output seen as an int, unsigned? kind of confusing, thanks for help !

Ok, your assignment says 3 char inputs. I think you are over complicating things here. Something like:

Code:

---

void chartodecimal(){
    char a,b,c;
    unsigned int number;
    cin>>a>>b>>c;
    ..do your conversion...
    cout << number;
}

---

Thanks Andrew that made more sense, however in the conversion output I am getting weird numbers, I know this is due to the ascii code table which has 255 characters according to Ascii Table - ASCII character codes and html, octal, hex and decimal chart conversion.
I am trying my output to be the same as the input. Whenever i do

123 my output becomes as 49,

Code:

---

void c(){
        char x,y,z;
    unsigned int digit;
    cin>>x>>y>>z;
        digit = (x),(y),(z); // 123 in output is 49?
    cout << digit;

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That is because you are suppose to convert those characters into 1 unsigned integer, per your assignment. That is not how you convert them. This is a basic conversion, if I gave you two characters, '5' and '0' in that order, how would you convert them to the number 50? e.g. 5 times what? + 0 times what?

Think about how the decimal number system works. The number 256 is 2 what, 5 what, and 6 what?

Quote:

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Originally Posted by AndrewHunter

That is because you are suppose to convert those characters into 1 unsigned integer, per your assignment. That is not how you convert them. This is a basic conversion, if I gave you two characters, '5' and '0' in that order, how would you convert them to the number 50? e.g. 5 times what? + 0 times what?

Think about how the decimal number system works. The number 256 is 2 what, 5 what, and 6 what?

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well i keep thinkin arithmetically, you'd multiply 5x10 and 0x10 as well? to give you 50? My teacher keeps telling us that compiler does not use understand basic arithmetic rules
so I might be wrong the answer I just gave I do see the over all idea nonetheless if you could give me an example I'd grasp from there,

Ok, let's do an example. I give you the number 1035. To break this up we would go by the decimal place values:
1 x 1000 = 1000
0 x 100 = 0
3 x 10 = 30
5 x 1 = 5

Then we would add all those up: 1000 + 0 + 30 + 5 = 1035. Do you see?

Quote:

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// CS 575 HW 3

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Odd...CS 575 implies that you are not an amateur or a beginner, as stated in your first post. Does your school do something wacky, like start you off in 500-level courses, with 100-levels being the final year courses? Just a non-standard nomenclature, AFAIK. Heck, most 500-level courses are grad school courses.

(Just an aside...oddities fascinate me)

Awesome, so for my problem I understand that:
x takes value of 100s
y takes value of 10s and
z takes value of 1s

I tried to do the conversion as follows
digit =(x+100)+(y+10)+(z+1) however my silly attempt did not work.

Quote:

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Originally Posted by rags_to_riches

Odd...CS 575 implies that you are not an amateur or a beginner, as stated in your first post. Does your school do something wacky, like start you off in 500-level courses, with 100-levels being the final year courses? Just a non-standard nomenclature, AFAIK. Heck, most 500-level courses are grad school courses.

(Just an aside...oddities fascinate me)

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well the college I go to offers many programming classes, the teachers itself do make fun of the classes as my next semmester class is cs 570 which is java but you start at 575 which gives you the abcs of programming in which i am stuck :)

Quote:

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Originally Posted by elpedoloco

Awesome, so for my problem I understand that:
x takes value of 100s
y takes value of 10s and
z takes value of 1s

I tried to do the conversion as follows
digit =(x+100)+(y+10)+(z+1) however my silly attempt did not work.

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It would be (x * 100) + .... Come on now, turn your brain on.

Your school is weird :)

Quote:

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Originally Posted by AndrewHunter

It would be (x * 100) + .... Come on now, turn your brain on.

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Sorry Andrew, I do appreciate your help, I am just getting some weird compiler outputs I keep getting big numbers;
I understood how each character takes place depending on the digit and thus we must multiply that char by its digit, however I know that I must tell the compiler to
perform an operation with the asquii code overall numbers so it does not confuse my value for one of theirs.
Thats where I am currently stuck at the moment, Thanks again Andrew you've been greater help than my teacher.

Code:

---




//  CS 575 HW 3

#include <iostream>
#include <string>
using namespace std;


void c();
void d();
void e();
void f();
void g();
void h();

bool die( const string & msg );

int main(){


    c();
    d();
    e();
    f();
    g();
    h();

}



void c(){
        char x,y,z;
    int digit;
    cin>>x>>y>>z;
        digit=(x*100)+(y*10)+(z*1); // this operation seems to get the value of asquii code of a,b,c and then multiply by 100,10,1
    cout << digit;
               
}    //  c

void d(){

}    //  d

void e(){
}    //  e

void f(){
 
}    //  f

void g(){
 
}    //  g

void h(){
}    //  h


bool die( const string & msg ){
    cerr <<endl <<"Fatal error: " <<msg <<endl;
    exit( EXIT_FAILURE );
}  //  die

---

I see what you are saying now. A simple ASCII to decimal conversion is to subtract '0' from the number. So if you have char '5', to get number 5 you would do: '5'-'0'.( That is the char zero. )So in your case:

((x-'0')*100) + ....

Quote:

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Originally Posted by AndrewHunter

I see what you are saying now. A simple ASCII to decimal conversion is to subtract '0' from the number. So if you have char '5', to get number 5 you would do: '5'-'0'.( That is the char zero. )So in your case:

((x-'0')*100) + ....

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Thanks Andrew you been great help.

a,b,c,d,e,f,g,h ... best function names ever!

Quote:

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Originally Posted by iMalc

a,b,c,d,e,f,g,h ... best function names ever!

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It correlates with his assignments. I don't think he has a choice.