Help i need array+loop and count C++

Help i need array+loop and count C++

i need code for count the same value in array



Ex.
____________________________________________
Enter 10 #:1 2 3 4 4 4 4 4 4 5<---------------for array
Enter a Number: 4 <------------------entering the same for counting
Answer :6 <---------------------------- the Result
____________________________________________

this is my code:

#include <stdio.h>
int main()
{
int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
scanf("%d" ,&a[x]);
}
for(x=0;x<=9;x++)
{
}
printf("enter a number");
scanf("%d" ,&z);
if(z==a[x])
z++;
printf("answer is %d" ,z);
{
}
}





plsss help me
i hope you can help Me !!!!!!!

We can :D But first post your attempt please :) (in other words the code you have so far ) :)

Quote:

---

Originally Posted by std10093

We can :D But first post your attempt please :) (in other words the code you have so far ) :)

---

Code:

---

#include <stdio.h>
int main()
{
int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
scanf("%d" ,&a[x]);
}
for(x=0;x<=9;x++)
{
}
printf("enter a number");
scanf("%d" ,&z);
if(z==a[x])
z++;
printf("answer is %d" ,z);
{
}
}

---

• The check if the element of the array is the same as z has to be in the loop that goes through the whole array.
• Also z is not initialized to zero,as it ought to be.
• you should add a line return 0; at the end of main (this you should do it in general)
• tidy up your code style a bit.The bodies of the if and for must be one tab to the right

hope this helps :)

Sigh. This is not C++. This is C. Learn to know the language you study, please.

Quote:

---

Originally Posted by Elysia

Sigh. This is not C++. This is C. Learn to know the language you study, please.

---

Take it in stride instead of being frustrated. Different people make the same mistake, and have no idea and don't care who else has made the mistake.

As for the question, std10093 needs an extra bullet.
• x < 10 is the conventional form...

I believe in enlightening those who are in error. They have a right to know the difference between two entirely different languages.

i can`t run program perfectly help me!!!

enter # 1 2 3 4 4 4 4 4 4 4
enter # 4
answer 5

i want count the same value in array
like this

enter # 1 2 3 4 4 4 4 4 4 4
enter # 4
answer 7
help me!!!

can you please post your updated code ? :)
careful not to re-edit the old one,but to create a new post with the updated one :)

Quote:

---

Originally Posted by std10093

can you please post your updated code ? :)
careful not to re-edit the old one,but to create a new post with the updated one :)

---

Code:

---

#include <stdio.h>int main()
{
int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
scanf("%d" ,&a[x]);
}
for(x=0;x<=9;x++)
{
}
printf("enter a number");
scanf("%d" ,&z);
z=0;
z++;
printf("answer is %d" ,z);
return 0;
}

---

but now chage value to 1
enter # 1 2 3 4 5 6 7 8 8 8
enter # 8
answer 1

You should indent your code properly, e.g.,

Code:

---

#include <stdio.h>

int main()
{
    int a[10], x, z;

    printf("enter a number");
    for (x = 0; x <= 9; x++)
    {
        scanf("%d" , &a[x]);
    }

    for (x = 0; x <= 9; x++)
    {
    }

    printf("enter a number");
    scanf("%d", &z);
    z = 0;
    z++;
    printf("answer is %d", z);

    return 0;
}

---

Now, it is obvious that your second for loop has no net effect: it might as well not exist. Then, you read a number from the user and store it in z, but immediately assign 0 to z and increment it, hence the "answer is 1", always.

Let's take it step by step because i think you are a bit of confused :)
The goal is to produce code for count the same value in array (copy paste from your post)
So i need to declare an array and fill it with values.You did excellent here

Code:

---

int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
      scanf("%d" ,&a[x]);
}

---

Then i need to read a number.This number is what i have to search for in the array.We need to declare a variable in order to remember this number.You declared z and then you have this to read the input

Code:

---

printf("enter a number");
scanf("%d" ,&z);

---

So far so good.Now we have to count how many times this z is inside the array!So...we need an extra variable in order to count.As a result let's call it counter :)
From where should we start counting?From zero of course!But how can our code knows that?We will inform the code!How?Just by initializing the counter to zero ;)

Code:

---

int counter = 0;

---

Now you have to start searching :)
We need to go through the whole array,so we have to use a loop.In this loop we are going to check again and again if z is equal (remember, we use two signs of equal for comparison ) to the element of the array we check at a time,we should increase the counter by one.Something like this

Code:

---

for( x = 0 ; x < 10 ; x++)
{
        if(z == a[x])
        {
              counter++;/*This is equivalent to this counter = counter +1; and this counter+=1;*/
        }
}

---

Now try to put everything together.Why i do not did this for you?Because you will miss all the fun then ;)

Also remember from previous posts this

• tidy up your code style a bit.The bodies of the if and for must be one tab to the right
• x < 10 is the conventional form...

thanks to whiteflag for the second bullet :)

Tnx for the code std10093
now im try to remove this
Attachment 12043

Quote:

---

Originally Posted by std10093

Let's take it step by step because i think you are a bit of confused :)
The goal is to produce code for count the same value in array (copy paste from your post)
So i need to declare an array and fill it with values.You did excellent here

Code:

---

int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
      scanf("%d" ,&a[x]);
}

---

Then i need to read a number.This number is what i have to search for in the array.We need to declare a variable in order to remember this number.You declared z and then you have this to read the input

Code:

---

printf("enter a number");
scanf("%d" ,&z);

---

So far so good.Now we have to count how many times this z is inside the array!So...we need an extra variable in order to count.As a result let's call it counter :)
From where should we start counting?From zero of course!But how can our code knows that?We will inform the code!How?Just by initializing the counter to zero ;)

Code:

---

int counter = 0;

---

Now you have to start searching :)
We need to go through the whole array,so we have to use a loop.In this loop we are going to check again and again if z is equal (remember, we use two signs of equal for comparison ) to the element of the array we check at a time,we should increase the counter by one.Something like this

Code:

---

for( x = 0 ; x < 10 ; x++)
{
        if(z == a[x])
        {
              counter++;/*This is equivalent to this counter = counter +1; and this counter+=1;*/
        }
}

---

Now try to put everything together.Why i do not did this for you?Because you will miss all the fun then ;)

Also remember from previous posts this

• tidy up your code style a bit.The bodies of the if and for must be one tab to the right
• x < 10 is the conventional form...

thanks to whiteflag for the second bullet :)

---

What is your current code?

Quote:

---

Originally Posted by laserlight

What is your current code?

---

Code:

---

#include <stdio.h>main()
{
int a[10],x,z;
printf("enter a number");
for(x=0;x<=9;x++)
{
                scanf("%d" ,&a[x]);
}
printf("enter a number");
scanf("%d" ,&z);
int counter = 0;
for( x = 0 ; x < 10 ; x++)
{
                  if(z == a[x])
                  {
                                        counter++;
                        printf("answer %d" ,counter);
                        }
}
}

---

im trying to fix display answer in my own tnx a lot for
advice and this code

You should print the answer after the search .So you should move the printf out of the loop,because you want it to be executed only once ;)

Please fix the indentation of your code and post it again. In doing so, you may discover how to fix this problem that you're facing by yourself ;)

Quote:

---

Originally Posted by laserlight

Please fix the indentation of your code and post it again. In doing so, you may discover how to fix this problem that you're facing by yourself ;)

---

tnx for advice

tnx for helping me!!! laserlight and std10093

Code:

---

/* Input 10 numbers in an array and count the number of occurence of an element inside the array */
   

  #include<stdio.h>
  #include<conio.h>

  void main()

  {

      clrscr();

      int a[10],i,n,count=0;


      for(i=0;i<10;i++)

        {

              printf("\n\t Enter element a[%d] : ",i);
              scanf("%d",&a[i]);

          }

      printf("\n\n Enter the element you want to count : ");

      scanf("%d",&n);

      for(i=0;i<10;i++)

        {
            if(n==a[i])

              count++;

          }

    printf("\n\n %d occurs %d times in your array ",n,count);

    getch();

  }

---

Quote:

---

Will this work for you ?

---

I would have to say no, your code doesn't work for me. First several members of this forum have been telling the OP to properly format the code, so when you post poorly formatted code you to are not following their advice. I recommend you also learn to properly format your code it will make reading your code much easier. Second you change int main() to void main() which is also wrong main should never be defined to return a void, except in very rare circumstances. Lastly providing a complete solution you rob the student of the joy that comes from actually finding their own problems. Along with the fact that they will learn much less.

Jim

Hey Marvin,

You don't want to print "Enter a number" without giving more information. Maybe "Enter 10 numbers that will be searched through". Then "Enter a number to search for: ". Just something to give the user a chance at entering the right info - because otherwise, they won't do it.

How do you want the display answer?

Quote:

---

Originally Posted by jimblumberg

I would have to say no, your code doesn't work for me. First several members of this forum have been telling the OP to properly format the code, so when you post poorly formatted code you to are not following their advice. I recommend you also learn to properly format your code it will make reading your code much easier. Second you change int main() to void main() which is also wrong main should never be defined to return a void, except in very rare circumstances. Lastly providing a complete solution you rob the student of the joy that comes from actually finding their own problems. Along with the fact that they will learn much less.

---

And I would have to say pls dont try to discourage ppl who want to share and learn C-programming with such out-of-context comments...I have just provided the code that I had felt might work for the thread-starter...So, allow them to reply back with their opinion instead of showing-off ur ' I am the ultimate' attitude... There r more forums for that. We signed in here to learn and discuss C-programming , not to lambast others..

Quote:

---

Originally Posted by somali.cc

And I would have to say pls dont try to discourage ppl who want to share and learn C-programming with such out-of-context comments

---

Many of jimblumberg's comments critiqued your code. That is not out of context.

Quote:

---

Originally Posted by somali.cc

I have just provided the code that I had felt might work for the thread-starter.

---

As jimblumberg noted, please don't do that until it is clear that the thread starter has a working solution, in which case you would be providing an alternative solution for discussion. Thus, your code example would be excellently posted after Marvin Flores has posted one last code sample that he/she is quite satisfied with.