template with type=array?

I have this code:

Code:

---

#include <iostream>

using namespace std;

template <typename A>
void doodle(A dod)
{
    cout << "Size of dod is " << sizeof(dod) << "." << endl; 
}

int main()
{
    char dod[8];
   
    doodle(dod); 
   
    cin.get();
   
    return 0;
}

---

It prints "Size of dod is 4.", the size of a pointer. I wanted the template was instantiated with type char[8], not char*. Is it possible? I am using Gcc 3

Thanks any help

Code:

---

#include <iostream>

using namespace std;

template <typename A>
void doodle(A& dod)
{
    cout << "Size of dod is " << sizeof(dod) << "." << endl; 
}

int main()
{
    char dod[8];
   
    doodle(dod); 
   
    cin.get();
   
    return 0;
}

---

Wow! Thanks so much!

Er... could you explain it? The solution is so simple I almost feel an idiot.

Passing an array to a function, as in your original code, actually passes a pointer to the first element. sizeof therefore yields the size of that pointer, rather than the size of the array.