Passing a pointer as a reference

Hi,

I have a function name fun1(), in which there is a pointer say ptr1. I am passing this pointer to fun2() and in fun2() there are some changes that are being made to that pointer (say some increment or allocation to some structure).

I want that modification to be reflected in fun1(), i don't want to return it from fun2(). What i want is that fun2() receive this pointer as a reference to original pointer and any changing made to it will be reflected in fun1().

i am doing this

Code:

---

void fun1()
{
    someStruct *ptr = null;
    fun2(ptr);
    .
    .
    .
    ptr -> someThing = 3;
}

void fun2 (someStruct &ptr)
{
    ptr = new someStruct();
    ptr++;
}

---

but it is not working ... :(.

can you people help me ... please

> ptr++;
Incrementing the pointer itself, after you've allocated it is a sure way of messing up what happens next.

Code:

---

void fun1()
{
    someStruct *ptr = null;
    fun2(ptr);
    .
    .
    .
    ptr -> someThing = 3;
}

void fun2 (someStruct &ptr)
{
    ptr = new someStruct();
    ptr->omeThing = 0;
}

---

If fun2 is prototyped properly before you use it, should be ok.

To the OP:

Your code doesn't work because it's not valid C. It's C++. C doesn't have references.


Quzah.

Quote:

---

Originally Posted by quzah

To the OP:

Your code doesn't work because it's not valid C. It's C++. C doesn't have references.


Quzah.

---

Or the new keyword either for that matter.

Moved to C++

Or the null keyword for that matter. :) Unless you've defined null yourself, you should use NULL or just plain 0.

Code:

---

void fun2 (someStruct &ptr)
{
    ptr = new someStruct();
    ptr->omeThing = 0;
}

---

That code mixes pointers and references . . . it should be

Code:

---

void fun2 (someStruct *ptr)
{
    ptr = new someStruct();
    ptr->omeThing = 0;
}

---