invalid conversion from 'const char*' to 'char'

I'm trying to make a little code that makes a 2-dimensional character array and fills it with 0's(or a's or whatever char) for now.

it gives me this error when i compile:

Quote:

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invalid conversion from 'const char*' to 'char'

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here's the code:

Code:

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    int scrsizex=10, scrsizey=10;
    char scr[scrsizey][scrsizex];
   
    for (int county=0; county<scrsizey;county++){
        for (int countx=0; countx<scrsizex;countx++){
            scr[county][countx]="0";
            }
    }

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Compiling with Dev-C++ v4.9.9.2


Any ideas?

> scr[county][countx]="0";
Use
scr[county][countx]=0;
or
scr[county][countx]='\0';

Use the single quotes for letters.

ok, i thought i tried doing that but it didn't work... ok...


just ran it.
i think i had tried using ='0' and that's why it didn't work...
thanks!

Actually, '0' should work just as well as '\0'. They are two different letters. '0' is the character zero, while '\0' is the null character. If you print out '0', you will get zeros, but if you print out '\0' you will get nothing. In this case it would probably be better to use an actual character like '0', 'a', '*', ' ' (space), etc.

"0" would actually represent the address of that string and it is complaining because you are trying to assign the address of that string to a char variable when that variable isn't char*.

> scr[county][countx]="0";
You could write

scr[county][countx]="0"[0];

Or even
scr[county][countx]="0"[1];

/runs away

Code:

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int scrsizex=10, scrsizey=10;
char scr[scrsizey][scrsizex];

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You must use constant sizes, use 'const int' instead of 'int'.