Print Out Factors Of Numbers

i need to find the number of factors that are not greater than 1000 using a program built in C.

I have got everythin workin ok, but when it comes to printf() i dont know what to put or how to get it to load the numbers to do what im asking for.

everythin i have tried in printf isnt working, any ideas?

ok i'm gonna work on an assumption, (since you havent posted code) that your program looks a little like this:

Code:

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int main ()
{
        int a,b,c,d.....;
        float x,y,z.....;
        char something;  /*and so on*/

        /*body of program*/
        .
        .
        .
}

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here's how printf works:

Code:

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printf ("Integer is %d, Float is %f, Character is %c\n", a, x, something);

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That should help you out, but you really should supply some code so we can see what you may have done wrong.

Post your code.

ive got at the top int isfactorof and int numfactors with code underneath each. then i have got void main():

Code:

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void main()

{        int i,  result, max;

while(i<1000) {result = numberfactor (i);


if (result > max) { max = result;} i++;

printf("Number of Factors are:\n\n number = %d\n\n", max);

return;

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> void main()
main returns an int

> while(i<1000) {result = numberfactor (i);
There's nothing here to increment i, and since you don't initialise i either, the loop either does nothing at all, or gets stuck forever.

Quote:

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Originally Posted by Salem

> void main()
main returns an int

> while(i<1000) {result = numberfactor (i);
There's nothing here to increment i, and since you don't initialise i either, the loop either does nothing at all, or gets stuck forever.

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this is where i get lost, and dont know what to do on it.

what do i need to do so that i can fix this? what am i missing out?

Braces and indentation mostly.
Any consistent approach to formatting will make your code a lot easier to understand from the outset.

Code:

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int main ( ) {
    int i, result, max;
    i = 0;  /* added initialisers */
    max = 0;

    while ( i < 1000 ) {
        result = numberfactor (i);
        if (result > max) {
            max = result;
        }
        i++;
    } /* probably missing, I couldn't tell */

    printf("Number of Factors are:\n\n number = %d\n\n", max);

    return 0;  /* successful run, return 0 */
}

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