get all the right digits

How can i get the all right digit.... eg. input digit is 332, output is 32. Please see the below code and help me thanks

Code:

---

//Get all the right digits
int getRightDigit(int id)// eg. 332
{        int rtn;
        if (id < 10)
                return id%10;
        rtn = getRightDigit(id/10);
        printf("%d",rtn);
        return rtn;
}

---

the above code don't give u wanted, check out this

Code:

---

void getRightDigit(int id)
{
          if(id==0)
              return;
          else
              printf("%d  ",id%10);
              getRightDigit(id/10);
}

---

ssharish2005

Don't know witch one you want.

Code:

---

#include <stdio.h>

//Get all the right digits
//returns id if id < 10
int getRightDigit(int id) {
    int div = 10;
    while (( id / div )  > 10 )
        div *= 10;
    return id % div;
}

//Get all the right digits
//returns 0 if id < 10
int getRightDigit1(int id) {
    if ( id < 10 ) return 0;
    int div = 10;
    while (( id / div )  > 10 )
        div *= 10;
    return id % div;
}

int main(void) {
  printf( "%d \n" , getRightDigit(332) ); 
  printf( "%d \n" , getRightDigit1(2) ); 
  return 0;
}

---

Kurt

Thanks for your reply...but the code can't output 32 when i input 332...thanks

there u go

Code:

---

void getRightDigit(int id)
{
          if
          (id==0)
                          return;
    else
              printf("%d  ",id%100);
              getRightDigit(id/100);
}
/*my output
32  3
*/

---

ssharish2005

What's wrong with my solution ?
Kurt

Sorry Kurt...It's something error in my main program, so that it's wrong return...sorry ...thanks million for your help