function shift

Hi,

Trying to make the letters ABCDE shift by one by calling in five times i.e. BCDEA, CDEAB, DEABC, EABCD, and ABCDE.

Here's what I got and I know it's probably easy and I'm hosed up, but I'm an extreme noob at programming.

Thanks in advance.

Code:

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#include <stdio.h>

int main(void)

char  c1 = 'A', c2 = 'B', c3 = 'C', c4 = 'D', c5 = 'E';
char *p1 = &c1, *p2 = &c2, *p3 = &c3, *p4 = &c4, *p5 = &c5;

void shift(char *p1, char *p2, char *p3, char *p4, char *p5)
{
        shift(&c1, &c2, &c3, &c4, &c5);
        return 0;
}

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The tutorials section is the one that you should be heading to right now. Your code is so messed up, that i think you should start right from a hello world program. Also, you dont specify what you want to do with the shifted letters. Your aren't shifting them in an array, so i really dont understand what you intend to do.

mattflick this is not complete proper programe. you got many error in it. pointing out the error,
you havn't got the completed main fucntion.
you cant assign a value for an pointer
you cant use shift as an fucntion identifier as it is a inbuilt function identifier

and the proper code for you problem

Code:

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#include<stdio.h>

void shiftchar(char *p1, char *p2, char *p3, char *p4, char *p5)
{
    char temp;
   
    temp=*p1;
    *p1=*p2;
    *p2=*p3;
    *p3=*p4;
    *p4=*p5;
    *p5=temp;
}

int main()
{
    char  c1 = 'A', c2 = 'B', c3 = 'C', c4 = 'D', c5 = 'E';
    int i;
   
    for(i=0;i<5;i++)
    {
        shiftchar(&c1,&c2,&c3,&c4,&c5);
        printf("%c %c %c %c %c\n",c1,c2,c3,c4,c5);
    }
   
    getchar();
}
/*my output
B C D E A
C D E A B
D E A B C
E A B C D
A B C D E
*/

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and the better way of doing this using by string of char(strings)

-ssharish2005

Thanks so much for your help. I'm learning I just need more experience looking all the different types code for all there different applications. Thanks again for the help.