Playing with pointers

Consider this:

Code:

---

#include <stdio.h>

int main(void)
{
    int c;
    char *argv[] = {"hello", "world"};

    printf("%s\n", argv[1]);

    while (c = *(argv[1])++)
        putchar(c);

    return 0;
}

---

Is there another way to access the word "world"?

argv[1] is equivalent to *(argv + 1), but since they're the same thing just expressed differently, I don't know that I'd call that another way.

You could declare a pointer to argv and access it that way. :)

Is this allowed?

Code:

---

while (c = *(argv[1])++)

---

I'm pretty sure it's C99, but what about C89? I thought you had to go

Code:

---

while ((c = *(argv[1])++))

---

in C89.

dwks, why do you think C89 requires a redundant pair of parentheses there?

gcc with -Wall (and probably other compilers) will suggest an extra pair because it thinks you might have made a mistake, and meant ==. It can't tell that you know what you're doing and really want to assign a value to c and test the result instead of wanting to compare.