Doesn't print out?

#include <stdio.h>
#include <string.h>

int main()
{
char str2[2], str1[2]= "a";
int n = 127;

str2[1] = 0;
str2[0] = n;

strcat(str1 , str2 );

if( str1[1] == n )
printf( "%s\n" , str1 );

return 0;
}

I don't know what's happenning. When n = 97, 98 ... 127, the printf prints out str1 but from n = 128 onwards, it doesn't print out anymore. Why and how do I fix it?:confused:

Try this:

unsigned char str2[2], str1[2]= "a";
unsigned int n = 240;

Analyze the table of int to char conversions. Maybe 128 is a different number. Theoretically, it should work (logically) out. char and int are interchangeable.

--Garfield

This is a no brainer:

The range of a 'char' is: -128/+127

Ok, so a "string" is what? It's an array of characters.
Given this, is it really a surprise that it doesn't print them?

for( c=-128; c < 128; c++ ) if( isprint(c) ) putc(c);

Quzah.

quzah is right.

quzah, if I'm correct, don't you have to unsign the char to use the value of 128?

--Garfield

Quote:

---

don't you have to unsign the char to use the value of 128?

---

Yes for positive 128, but negative 128 is fine using two's complement.

Yeah, that's what I thought.

I think you can't use the number 128 cause the number 128 is formed in the binary system by 10000000 and the fist bit on the left (the 1) is used to define if the number is positive or negative, cause that te maximum number you can write in binary is 1111111 = 127 (decimal)

Then you would need the 32-bit.