Passing Class Array through Fucntion

I made a class called Box, which has a size of 100 . Then I made an array of 6 "Boxes" , now, the size if 600. However, when I pass this array into a function, and tries to use sizeof in the function, the size of the whole array becomes 4, how come?:(

Because C++ passes an array as a pointer to the first element. When you use sizeof, you're getting the size of a pointer, not an array. One solution is to pass the size as well:

Code:

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void f ( Box array[], size_t size );

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Or encapsulate the array ina class or structure and pass a reference to that:

Code:

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struct BoxArray {
  Box array[SIZE];
  size_t size;
};

void f ( BoxArray& ba );

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Or even pass a reference to the array. But then you have size limitations that you must adhere to:

Code:

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void f ( Box (&array)[10] );

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Quote:

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Originally posted by Prelude
Because C++ passes an array as a pointer to the first element. When you use sizeof, you're getting the size of a pointer, not an array. One solution is to pass the size as well:

Code:

---

void f ( Box array[], size_t size );

---

Or encapsulate the array ina class or structure and pass a reference to that:

Code:

---

struct BoxArray {
  Box array[SIZE];
  size_t size;
};

void f ( BoxArray& ba );

---

Or any of a number of other ways. But passing the size along with the array is the simplest.

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ahh, okay, thx.