Inverse printing.

I'm sure the answer will be really easy, however i need to have the output of this inversed so i get

Quote:

---

F
FE
FED
FEDC
FEDCB
FEDCBA

---

here is my code, please let me know what is wrong with it.

Code:

---

  /* alpha dependant nested loops.c */


#include <stdio.h>
#define ROW 6


int main(void)


{
    int row;
    char ltr;

    for (row = 0; row < ROW; row++){
        for (ltr = ('F' - row); ltr <('A' + ROW); ltr++)
            printf("%c", ltr );
        printf("\n");

        }


    getchar();

    return (0);


}

---

:confused:

Well, my preference would be to work with a string so that I wouldn't have to assume the ASCII character set:

Code:

---

#include <stdio.h>

int main ( void )
{
  char *p = "FEDCBA";
  int i, j;

  for ( i = 0; p[i] != '\0'; i++ ) {
    for ( j = 0; j <= i; j++ )
      printf ( "%c", p[j] );
    printf ( "\n" );
  }

  return 0;
}

---

But, with the right assumptions in hand, your way works too:

Code:

---

#include <stdio.h>

int main ( void )
{
  char i, j;

  for ( i = 'F'; i >= 'A'; i-- ) {
    for ( j = 'F'; j >= i; j-- )
      printf ( "%c", j );
    printf ( "\n" );
  }

  return 0;
}

---

Interesting, you used too char loops since its the same count as integers anyaway. Very interesting. I never thought about doing that. Thank you very much prelude.

Quote:

---

Well, my preference would be to work with a string so that I wouldn't have to assume the ASCII character set:

---

I haven't delved into pointers and strings yet, so i'm still a little behind. However i do understand your code with the char pointer? in it. I will be studying that code.


;)

The 'why' it isn't working can be found using a flowchart and your knowledge of standard 'C'.