I really need help!!! please!

i hope im doing this right, im sorry i dont know anything about programming. This was my assignment:
/*

MAE9: Homeworki #3, Spring 2003

Due on Thursday, April 24, before 11:00 pm



Create a table for monthly payments of a house loans.

Enter the price of a house from the keyboard, for example
price = 450000.

For annual interest rates: annual_rate = 0.045 to 0.075 with
the increment of 0.0025, compute by using the for-loop the
monthly payments for 15-year, 20-year, and 30-year loans.
Print the results in the table on the screen.

Then, copy the previous loop and modify it to calculate the
total payments after 15, 20, and 30 years. Print results in
another table on the screen.

Use the formula for equal-monthly-payments:

month_pay = price * i* (1 + i)^n/((1 + i)^n - 1)

where i= annual_rate/12. (monthly interest rate),
and n = the total number of payments.

The total payment for a given loan is:

tot = n * month_pay

To compute (1 + i)^n use pow(1.0 + i, (double)n)

Your output should look like this:

price = 450000.00

Monthly Payments

Ann. Int. Rates 15-year loan 20-year loan 30-year loan
------------------------------------------------------------------
0.0450 3442.47 2846.92 2280.08
0.0475 3500.24 2908.01 2347.41

...... ....... ....... .......

0.0750 4171.56 3625.17 3146.47



Total Payment

Ann. Int. Rates after 15 yr after 20 yr after 30 yr
-----------------------------------------------------------------
0.0450 619644.56 683261.33 820830.20
0.0475 630043.85 697921.52 845068.69

...... ......... ......... .........

0.0750 750880.01 870040.65 1132727.50

*/
and this is my attempt:

Code:

---

#include<stdio.h>
#include<math.h>
main()
{
printf("\t\t\tMonthly Payments\nAnn. Int. Rates\t15-year loan\t20-year loan\t30-
year loan\n--------------------------------------------------------------\n");
int k;
double r, m1, m2, m3, tot1, tot2, tot3, n, m, o, p, b;
p=450000;
n=180;
m=240;
o=360;
for(k=1; k<=12; k++)
{
r = (.0450+(.0025*(k))),k;
b = ("(r) /12."),r;
m1 ={((p)*(b)*(1 + b) ^(n)}/{((1+b) ^(n)-1))};
m2 ={((p)*(b)*(1 + b) ^(m)}/{((1+b) ^(m)-1))};
m3 ={((p)*(b)*(1 + b) ^(o)}/{((1+b) ^(o)-1))};
tot1 = (n * m1);
tot2 = (m * m2);
tot3 = (o * m3);
printf("\t%1.4f\n",r);
}
}

---

What's the problem. Contrary to popular believe, none of us (with the exception of the Moderators) are telepathic.

On a side note, code tags do little good if you don't bother actually indenting anything...

Additionally, ^ is not the "power" operator. It's a XOR. You definately do not want this. (Especially since floating point numbers should have your compiler throwing fits when you try to use it.)

Quzah.

im sorry, im brand new at this im using ssh secure shell program to write this and i dont know anything about indenting. all i know is when i try to run it it keeps giving me these errors
HW3.c: In function `main':
HW3.c:15: incompatible types in assignment
HW3.c:16: parse error before '{' token
HW3.c:17: parse error before '{' token
HW3.c:18: parse error before '{' token
and i guess i have to use scanf or something to enter the price 450000 instead of just listing it, and every time i try that it says core dump

Code:

---

#include<stdio.h>
#include<math.h>
main()
{
double num1;
printf("enter price:\n");
scanf("%d", num1);
printf("price = %d\n",num1);

---

this is what happens:
iacs5.ucsd.edu 50: gcc Hw3.c -lm
iacs5.ucsd.edu 51: a.out
enter price:
45000
Segmentation fault (core dumped)

*if theres anything else i can put to help express what the problem is please tell me im sorry i dont know anything

Scanf expects pointers. As such, you need to pass it the address of the variable:

scanf( "%d", &myvar );

Notice the "&" sign.

Quzah.

if ^ is not a power what is a power?

^ is the xor if I'm not misken

pow(a, b) along with math.h or cmath

I tried doing the & thing and this it still gave me a core dump, and i changed the ^ sign, thanks for all your help i really appreciate it

Code:

---

#include<stdio.h>
#include<math.h>
main()
{
double num1, p;
printf("enter price:\n");
scanf("%f", &p);
printf("\t\t\tMonthly Payments\nAnn. Int. Rates\t15-year loan\t20-year loan\t30-
year loan\n--------------------------------------------------------------\n");
int k;
double r, m1, m2, m3, tot1, tot2, tot3, n, m, o, b;
n=180;
m=240;
o=360;
for(k=.045; k<=.075; k=k+.0025)
{
b = ("(k) /12."),k;
m1 = (p)*(b)*(pow(1 + b, (double)n))/(pow(1+b, (double)n)-1);                 
m2 = (p)*(b)*(pow(1 + b, (double)m))/(pow(1+b, (double)m)-1);                 
m3 = (p)*(b)*(pow(1 + b, (double)o))/(pow(1+b, (double)o)-1);                 
tot1 = (n * m1);
tot2 = (m * m2);
tot3 = (o * m3);
printf("\t%1.4f\n",r);
}
}

---

and this is what it told me when i tried to run it:

Code:

---

HW3.c: In function `main':
HW3.c:16: incompatible types in assignment
iacs5.ucsd.edu 206: a.out
enter price:
45000
Segmentation fault (core dumped)

---

>>b = ("(k) /12."),k;

What is this for? This will not work.

since p is a double, try using %lf.

You're using k as a floating point, but you've delcared it as an int. I *think* it's truncating that loop to 0, but...

use the %lf for your output too.

i tried switching it to %lf and its still not going through and the whole line with b = ("(%lf) /12."), r; is because in the later equations i need the monthly interest rate which is the annual interest rate (%lf) divided by 12, if you could tell me another way to write it so that it would work thatd be great. heres what i have now and what it tells me, thanks so much for helping me out here:

Code:

---

#include<stdio.h>
#include<math.h>
main()
{
double num1, p;
printf("enter price:\n");
scanf("%d",&p);
printf("\t\t\tMonthly Payments\nAnn. Int. Rates\t15-year loan\t20-year loan\t30-
year loan\n--------------------------------------------------------------\n");
int k;
double r, m1, m2, m3, tot1, tot2, tot3, n, m, o, b;
n=180;
m=240;
o=360;
for(k=0; k<=12; k++)
{
r=(.0450+(.0025*k)), k;
b = ("(%lf) /12."), r;
m1 = (p)*(b)*(pow(1 + b, (double)n))/(pow(1+b, (double)n)-1);
m2 = (p)*(b)*(pow(1 + b, (double)m))/(pow(1+b, (double)m)-1);
m3 = (p)*(b)*(pow(1 + b, (double)o))/(pow(1+b, (double)o)-1);
tot1 = (n * m1);
tot2 = (m * m2);
tot3 = (o * m3);
printf("\t%1.4f\n",r);
}
}

---

and what it says:

Code:

---

HW3.c: In function `main':
HW3.c:17: incompatible types in assignment

---

im sorry also if anyone knows how to get it to stop core dumping cause ive tried adding a & and changing the first part from %f to %d neither worked so far.
thanks