Variable Names based on Variable Values

greetings,

i wasnt to sure what to name the subject but what im trying to do is basically display variables based on the value of another variable. consider this...

char Name1[10] = "Test1";
char Name2[10] = "Test2";
int Value = 2;

now rather than doing

switch(Value)
{
case 1:
cout << Name1 << endl;
break;

case 2:
cout << Name2 << endl;
}

could i instead do somethign along the lines of


cout << NameValue << endl;

ie. appending the value of "Value" in this case "2" to that of Name and thus printing the value of Name2 ?

im trying to do this with structures so i have enemies1, enemies2, enemies3, etc, etc based on what level player is on. Therefore rather than using switch and cases if I coudl just append the value of what level they are on to "enemies" and thus pulling the correct data.

I have dont this before in PHP but not sure if its possible with C++.

I hope you can understand what i mean.

Thanks in advance for any advice given.

Store the Names in a two dimensional array.

Code:

---

#include <iostream>
using namespace std;

int main()
{
        char Names[2][10] = {"Test1", "Test2"};
        int i;

        i = 0;
        cout << Names[i] << endl;
        ++i;
        cout << Names[i] << endl;

        return 0;
}

---

No, you can't do it like that. There are a couple of ways to do this, the easiest - although probably not the best - would be to make them into a two-dimensional array like so:

Code:

---

char Name[1][10] = "Test1";
char Name[2][10] = "Test2";
int Value = 2;

cout<<Name[value]<<endl;

---

Another option is to use a map

Code:

---

#include <iostream>
#include <string>
#include <map>

using namespace std;

int main()
{
  map<int, string> tbl;
  string Name1 = "Hi", Name2 = "there!";

  tbl[1] = Name1;
  tbl[2] = Name2;

  cout<< tbl[2] <<endl;
}

---

If you're exceptionally daring you can use the preprocessor to paste things together, this isn't a recommended solution though. :-)

Code:

---

#include <iostream>
#include <string>

#define call_name(x) (Name##x)

using namespace std;

int main()
{
  string Name1 = "Hi";
  string Name2 = "there!";

  cout<< call_name(2) <<endl;
}

---

Thanks for your replies and I follow what you are saying however im looking to do this with structure names.

for example.

Code:

---


struct enemy
{
  char name[50];
  int whatever;
}

enemy level1[] =
{
  {"Dog", 10},
  {"Cat", 20}
}

enemy level2[] =
{
  {"Chicken", 30},
  {"Horse", 40}
}

int main()
{
  int CurrentLevel = 2;
  cout << levelCurrentLevel[0].name << endl;
}

---

so im using that value of CurrentLevel to pull the corresponding data from the correct Structure.

so im not sure how i can incorporate your two-dimensional array into this ?

Thank You

>>so im not sure how i can incorporate your two-dimensional array into this ?
Something like this would be simple enough. :-)

Code:

---

#include <iostream>

using namespace std;

struct enemy
{
  char name[50];
  int whatever;
};

enemy level1[] =
{
  {"Dog", 10},
  {"Cat", 20}
};

enemy level2[] =
{
  {"Chicken", 30},
  {"Horse", 40}
};

static enemy *level[] = {
  0, // No level0?
  level1,
  level2,
};

int main()
{
  int CurrentLevel = 2;
  cout << level[CurrentLevel][0].name << endl;
}

---

Thank you very much :)