Return / Exit Issue

Hi all,
This is my first post here! I have two questions:

1. I'm learning C by using 'Sams Teach yourself C for Linux Programming in 21 days'. I have finished the first week and have difficulties with the end-of-week programme. My problem is with a function called 'display()'. It is a void function so there is no return statement. But yet, I get the following error message from GCC:

'in function "disply()"'
'use "return" to return in void function'

The message is very similiar to the above one but not exactly the same. Can anyone help?

2. If I want to display the following message and then immediately quit the programme when I'm not in the main function
what do I do?

' if(cont == NO)
{
printf("Programme aborted by user!");
/* what's the command for exiting? It goes here */
}

You can use return to exit a void function, it will just not return a value to the calling function :

Code:

---

void testFunc()
{
 // do stuff
 if ( ????? )
 {
  return;
 }
  // do stuff
}

---

This is usefull if you want to exit a function under certain conditions.

To exit a program from a function you can use exit(exitcode) :

Code:

---

exit(0); // exits with error code of 0

---

Thanx,
I'll try that but I think I've already tried 'return;' with nothing in front of it but it doesn't hurt to try again...

Use return(); for type void functions. Sometimes picky compilers make you do that.

-Will

Quote:

---

Originally posted by C-Duddley
Use return(); for type void functions. Sometimes picky compilers make you do that.

-Will

---

nope nope nope wrong wrong wrong nope nope nope wrong wrong wrong nope nope nope wrong wrong wrong.

anyway Rhodium, give me the EXACT WORDS of your error message